Question

Asked Mar 12, 2019

what can be stated about the graph of f(x) given

lim f(x)=2/3

x→−∞

a. f(x) has a horizontal aymptote aat y=2/3

b.f(x) has no horizontal asymptotes

c.f(x) has no vertical asymptotes

d.f(x) is discontinuos when x=2/3

Step 1

The horizontal line *y = b* is called a horizontal asymptote of the graph of *y = f(x)* if either

Step 2

The given expression states that the value of *f(x) *goes to 2/3 as *x* tends to negative infinity.

As per the definition of horizontal asymptote, it implies that the graph of the fu...

Tagged in

Q: Find the area of the surface generated when the given curve is revolved about the given axis. y 10x ...

A: Given:

Q: Use the derivative f'(x) = (x - 3)(x + 4)(x + 4) to determine the maxima and minima of f and the int...

A: f will be increasing if f'(x)>0. From the graph of f'(x) we see f'(x)>0 when x>3 [because a...

Q: How can I get the result? Which is the result?

A: (a)we are given a function

Q: Help please..

A: The general Taylor series for ex at x = 0 is as follows.

Q: Answers for 10-12

A: We will solve Q-10

Q: could you help me with this problem please

A: Given,

Q: I need help with this please. How do I find the volume generated by revolving the region bounded by ...

A: Given information:The region bounded by y = -sinx and y=0, from x= -2pi to x=0, about the x-axis

Q: Find the area of the region that lies inside both curves. r = 9 + cos(θ), r = 9 − cos(θ)

A: To calculate the area of the given region (by integration) described by polar coordinates

Q: Evaluate the following integral.

A: The given integral is,