What could be the value of the register Stl after executing the instruction SLL Stl, $tO, 1 if the value of St0=1010 0110 1100 0001 0000 0000 0000 0001?5t1=0101 0011 0110 0000 1000 0000 0000 0001bl StI=0100 1101 1000 0010 0000 0000 0000 0010c) 5t1=0101 0011 0110 0000 1000 0000 0000 0000d) St1=1100 1101 1000 0010 0000 0000 0000 0010

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Asked Nov 13, 2019
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What could be the value of the register Stl after executing the instruction SLL Stl, $tO, 1 if the value of St0=1010 0110 1100 0001 0000 0000 0000 0001?

5t1=0101 0011 0110 0000 1000 0000 0000 0001

bl StI=0100 1101 1000 0010 0000 0000 0000 0010

c) 5t1=0101 0011 0110 0000 1000 0000 0000 0000

d) St1=1100 1101 1000 0010 0000 0000 0000 0010

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Expert Answer

 

Answer:

The value stored in $t0=1010 0110 1100 0001 0000 0000 0000 0001

SLL(Shift Left Logical) which means shifting one bit to its left.

By shifting the $t0 to one bit left, the value stored in register $t1 is 0100 1101 1000 0010 0000 0000 0000 0010.

Here, the zeros are rep...

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