What is the β D.C of a transistor if I C = 30.5 mA and I E = 30.7 mA?

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What is the β D.C of a transistor if I C = 30.5 mA and I E = 30.7 mA?

Expert Solution
Step 1

Given:

IC=30.5 mAIE=30.7 mA

Step 2

For a transistor

IE=IC+IB

Substituting the given values

30.7=30.5+IBIB=30.7-30.5IB=0.2 mA

Now

βDC=ICIB=30.5 mA0.2 mAβDC=152.5

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