What is the Kb of the base PO−34 given that a 0.48M solution of the base has a pH of 12.70? The equation described by the Kb value is PO−34(aq)+H2O(l)⇌HPO−24(aq)+OH−(aq)   Report your answer with two significant figures.

Chemistry: The Molecular Science
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Chapter17: Electrochemistry And Its Applications
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What is the Kb of the base PO−34 given that a 0.48M solution of the base has a pH of 12.70? The equation described by the Kb value is

PO−34(aq)+H2O(l)⇌HPO−24(aq)+OH−(aq)

 

Report your answer with two significant figures.

What is the Kp of the base PO, given that a 0.48 M solution of the base has a pH of 12.70? The equation described by the
K, value is
PO, (aq) + H2 O(1) = HPO, (aq) + OH¯(aq)
Transcribed Image Text:What is the Kp of the base PO, given that a 0.48 M solution of the base has a pH of 12.70? The equation described by the K, value is PO, (aq) + H2 O(1) = HPO, (aq) + OH¯(aq)
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