what is the limit of
lim xsinx / 2-2cosx
x--0
problems online show l'hopitals rule but i was wondering if there is another way to solve it without using that rule
To determine the value of limit without using L hospital rule
xsin limx0 2 2 cos.x
Apply the limit o...
xsinx limx0 2-2 cosx rsinx(1cos.x 2-2 cos.x (1+cos x) limx0 xsinx-(1cosx limx0 2(1-cosx)(1+cosx) limx0sinr-(1+cosx 2(1-cos'x) limx0Sinr-(1+cosx) 2sin2 x 1-cos'xsin x limr (1+ cos.x) 2sinx x(1+cos.x) limx0 sinx 2 limr +cos.r) 2 limx0 sinx (1+cos0) 1+1 cos0-1} 2 2 (1+cos0) = 1 2
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