Question
Asked Sep 4, 2019

What is the mole fraction of 120 g NaOH in 1 L (1000g) of water?

check_circleExpert Solution
Step 1

Molecular mass of sodium hydroxide = 40 g.

Number of moles of sodium hydroxide = 120/40 = 3 moles.

Molecular mass of sodium hydroxide = 40 g.

Number of moles of sodium hydroxide = 120/40 = 3 moles.

Number of moles of water= 1000/18=55.55 moles.

Number of moles of water= 1000/18=55.55 moles.

Step 2

Mole fraction of sodium hydroxide = Number of moles of solute&divid...

3
3+55.55
3
58.55
0.0512
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3 3+55.55 3 58.55 0.0512

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