x 8What is the NEXT step in solving this system of equations, andwhat is the solution for the value of "y"?O Go back to one of the original equations (you can choose either one) andplug in 8 for x; y = 2Go back to one of the original equations (you have to choose the 2ndequation) and plug in 8 for x; y = 2O Go back to one of the original equations (you can choose either one) andplug in 8 for x; y = -2O There isn't a NEXT step; The problem is completed solved! Solve the system. 2x 5y 6 and 3x y 26We can create opposites by multiplying the entire 2nd equation by 5. Thiswill give us a 5y and a -5y that will cancel.Multiply the entirebottom equation by 5The new equation now hasterms that are opposites.2x 5y 6+5(3x + y = 26)2x - 5y 6+ 15x+ 5y = 130%3D%3!2x 5y 6+ 15x + 5y = 130= 13617x+ Oy =17x 13617 17x 8What is the NEXT step in solving this system of equations, andwhat is the solution for the value of "y"?

Given equations are- 2x-5y=6& 3x+y=26 As in the given question, we have already found the value…

Answered: What is the NEXT step in solving this…

Math

Algebra

What is the NEXT step in solving this system of equations, and what is the solution for the value of "y"?

Algebra for College Students

10th Edition

ISBN:9781285195780

Author:Jerome E. Kaufmann, Karen L. Schwitters

Publisher:Jerome E. Kaufmann, Karen L. Schwitters

Chapter13: Conic Sections

Section13.5: Systems Involving Nonlinear Equations

Problem 39PS

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Question

x 8
What is the NEXT step in solving this system of equations, and
what is the solution for the value of "y"?
O Go back to one of the original equations (you can choose either one) and
plug in 8 for x; y = 2
Go back to one of the original equations (you have to choose the 2nd
equation) and plug in 8 for x; y = 2
O Go back to one of the original equations (you can choose either one) and
plug in 8 for x; y = -2
O There isn't a NEXT step; The problem is completed solved!

Solve the system. 2x 5y 6 and 3x y 26
We can create opposites by multiplying the entire 2nd equation by 5. This
will give us a 5y and a -5y that will cancel.
Multiply the entire
bottom equation by 5
The new equation now has
terms that are opposites.
2x 5y 6
+5(3x + y = 26)
2x - 5y 6
+ 15x+ 5y = 130
%3D
%3!
2x 5y 6
+ 15x + 5y = 130
= 136
17x+ Oy =
17x 136
17 17
x 8
What is the NEXT step in solving this system of equations, and
what is the solution for the value of "y"?

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