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What is the solution to the initial value problem below?y′=5ex +8x3 +x2 +4xy(0)=3Do not include "y=" in your answer.


What is the solution to the initial value problem below?

y′=5ex +8x3 +x2 +4x
Do not include "y=" in your answer.


Step 1

The given differential equation is, y′=5ex +8x3 +x2 +4x.

Step 2

Integrate both the sides of dy=(5ex +8x3 +x2 +4x)dx

Step 3

Where C is the integration constant.

Since y(0)=3 is given.

Substitute y=3 and x=0 ...


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