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Asked Sep 29, 2019
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what mass of iron (III) hydroxide percipitate can be produced by reacting 86.0 mL of 0.110M iron (III) nitrate with 101 mL of 0.230 M sodium hydroxide?

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Fe(NO) +3NaOH Fe(OH3 Na (NO,) No.of moles of Fe (NO3), =ConcxVolume 86.0 -L 9.46x 103 mol 1000 -0.110 Mx No.of moles of N2OH = ConcxVolume 101 L 0.02323mol 1000 0.230 Mx

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