Asked Mar 24, 2020

When 2.818 g of potassium hydrogen phthalate (symbolized here as KHPh; molar mass =204.2 g/mol) is titrated with KOH solution, it takes 31.74 mL of the base to achieve the end point. Calculate the concentration of the KOH solution.


Expert Answer

Step 1

Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, and mass with molarity is as given below;

Chemistry homework question answer, step 1, image 1

Step 2

The balance chemical reaction between potassium hydrogen phthalate and KOH can be written as:

Chemistry homework question answer, step 2, image 1

Step 3

Mass of potassium hydrogen phthalate=2.818 g

Molar mass of potassium hydrogen phthalate = 204.2 g/mol

Calculate the moles of potassium hydrogen phthalate:

Chemistry homework question answer, step 3, image 1


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