When 2.818 g of potassium hydrogen phthalate (symbolized here as KHPh; molar mass =204.2 g/mol) is titrated with KOH solution, it takes 31.74 mL of the base to achieve the end point. Calculate the concentration of the KOH solution.

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Chapter9: Acids, Bases, And Salts
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Problem 9.98E
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When 2.818 g of potassium hydrogen phthalate (symbolized here as KHPh; molar mass =204.2 g/mol) is titrated with KOH solution, it takes 31.74 mL of the base to achieve the end point. Calculate the concentration of the KOH solution.

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