Question
Asked Nov 8, 2019
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When 24.0 g of calcium metal is reacted with water, 5.00 g of calcium hydroxide is produced. Using the following balanced equation, calculate the percent yield for the reaction.

Ca(s) + 2 H2O(l) → Ca(OH)2(aq) + H2(g)

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Expert Answer

Step 1

Given data

Mass of calcium = 24.0g

Mass of calcium hydroxide= 5.0g

Step 2

Moles of Calcium

mass given
moles=
molar mass
24
0.6moles
40
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mass given moles= molar mass 24 0.6moles 40

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Step 3

According to the...

1 mole of Ca gives 1 mole of Ca(OH)
0.6 moles of Ca would give 0.6 moles of Ca (OH)
mass of Ca (OHmoles x molar mass
= 0.6 mol x 74g
44.4g
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1 mole of Ca gives 1 mole of Ca(OH) 0.6 moles of Ca would give 0.6 moles of Ca (OH) mass of Ca (OHmoles x molar mass = 0.6 mol x 74g 44.4g

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