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When 3.0 L of propane C3H8 gas is completely combusted to form water vapor and carbon dioxide at STP, what mass of water vapor will result? Molar mass: C3H8 = 44.11 g/mol, O2 = 32.00 g/mol, CO2 = 44.01 g/mol, H20 = 18.02 g/mol C3Hg(g) + 5 02(g) -> 3 CO,(g) + 4 H20(g)

When 3.0 L of propane C3H8 gas is completely combusted to form water vapor and carbon dioxide at STP, what mass of water vapor will result? Molar mass: C3H8 = 44.11 g/mol, O2 = 32.00 g/mol, CO2 = 44.01 g/mol, H20 = 18.02 g/mol C3Hg(g) + 5 02(g) -> 3 CO,(g) + 4 H20(g)

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter10: Gases And Their Properties
Section10.4: Gas Laws And Chemical Reactions
Problem 1RC: Diborane reacts with O2 to give boric oxide and water vapor. B2H6(g) + 3 O2(g) → B2O3(s) + 3...
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When 3.0 L of propane C3H8 gas is completely combusted to form water vapor and carbon dioxide at STP, what mass of water vapor will result? Molar mass: C3H8 = 44.11 g/mol, O2 = 32.00 g/mol, CO2 = 44.01 g/mol, H20 = 18.02 g/mol C3Hg(g) + 5 02(g) --> 3 CO2(g) + 4 H20(g) x Clear + Undo A Redo
Transcribed Image Text:When 3.0 L of propane C3H8 gas is completely combusted to form water vapor and carbon dioxide at STP, what mass of water vapor will result? Molar mass: C3H8 = 44.11 g/mol, O2 = 32.00 g/mol, CO2 = 44.01 g/mol, H20 = 18.02 g/mol C3Hg(g) + 5 02(g) --> 3 CO2(g) + 4 H20(g) x Clear + Undo A Redo
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