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When 5.967 x 10-1 mol of NH3 and 5.967 x 10-1 mol of O2 are introduced into a 1.976 L reaction vessel at a certain temperature a chemist finds that at equilibrium the N2 concentration is 1.317 x 10-1 M:4NH3(g) + 3O2(g) <==> 2N2(g) + 6H2O (g)What is the value of Kc for this reaction ?

Question

When 5.967 x 10-1 mol of NH3 and 5.967 x 10-1 mol of O2 are introduced into a 1.976 L reaction vessel at a certain temperature a chemist finds that at equilibrium the N2 concentration is 1.317 x 10-1 M:

4NH3(g) + 3O2(g) <==> 2N2(g) + 6H2O (g)

What is the value of Kc for this reaction ?

check_circleAnswer
Step 1

An equilibrium constant  is the ratio of concentration of products and reactants raised to appropriate stoichiometric coefficient at equlibrium.

An equilibrium constant (K) is the ratio of concentration of products and reactants raised
to appropriate stoichiometric coefficient at equlibrium
For the general reaction
aA bBcC+dD
The relative strength ofreaction can be also expressed quantitatively with an equilibrium
constant as follows:
(aC) (aD)
к.
(aA)(aB)
(1)
An equilibrium constant is (K )
help_outline

Image Transcriptionclose

An equilibrium constant (K) is the ratio of concentration of products and reactants raised to appropriate stoichiometric coefficient at equlibrium For the general reaction aA bBcC+dD The relative strength ofreaction can be also expressed quantitatively with an equilibrium constant as follows: (aC) (aD) к. (aA)(aB) (1) An equilibrium constant is (K )

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Step 2

concentration of the given compound is calculated

The reaction is shown below
4NH, (g)+30,(g) - 2N.(g)+6H,O(g)
K of the reaction is calculated as follows,
Moles
Concentration Volume
Moles
Concentration of NH,- Volume
Concentration of NH.= 5967x10
1976
Concentration of NH,=0.301
Concentration ofO.= 5.967 x10
1976
Concentration of O,-0.301
help_outline

Image Transcriptionclose

The reaction is shown below 4NH, (g)+30,(g) - 2N.(g)+6H,O(g) K of the reaction is calculated as follows, Moles Concentration Volume Moles Concentration of NH,- Volume Concentration of NH.= 5967x10 1976 Concentration of NH,=0.301 Concentration ofO.= 5.967 x10 1976 Concentration of O,-0.301

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Step 3

At equilibrium the concentration of...

ICE table:
бH, О(3)
4NH, g)
30, (g)
2N, (g)
Initial
0.301 M
0.301
0
0
concentration
Change
-3x
2x
+6x
-4x
At equilibrium
0.301-4*
0.301-3x
2x
- бх
At equilibrium
N.J-2x
2x1317x10
x0.066
Concentration of [H,0]
HO] 6x-6(0.066)
HO0.395 M
help_outline

Image Transcriptionclose

ICE table: бH, О(3) 4NH, g) 30, (g) 2N, (g) Initial 0.301 M 0.301 0 0 concentration Change -3x 2x +6x -4x At equilibrium 0.301-4* 0.301-3x 2x - бх At equilibrium N.J-2x 2x1317x10 x0.066 Concentration of [H,0] HO] 6x-6(0.066) HO0.395 M

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