When HBr adds to (CH3)2C = CH2 under radical conditions, two radicals are possible products in the first step of chain propagation. Draw the structure of both radicals and indicate which one is formed. Then draw the preferred product from HBr addition under radical conditions.

Question
Asked Dec 29, 2019
8 views

When HBr adds to (CH3)2C = CH2 under radical conditions, two radicals are possible products in the first step of chain propagation. Draw the structure of both radicals and indicate which one is formed. Then draw the preferred product from HBr addition under radical conditions.

check_circle

Expert Answer

Step 1

When HBr is added to (CH3)2C=CH2 under radical conditions, the major product formed is 1-bromo-2-methylpropane. The reaction follows Anti-Markovnikov’s rule. According to this, the positive part (H) of HBr goes to carbon having less number of hydrogen and negative part (Br) of HBr goes to carbon having a greater number of hydrogens.

The corresponding reaction is shown below.

Chemistry homework question answer, step 1, image 1
fullscreen
Step 2

In the above reaction, two radicals are formed as an interme...

Chemistry homework question answer, step 2, image 1
fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Chemistry

Organic reactions

Related Chemistry Q&A

Find answers to questions asked by student like you
Show more Q&A
add