munative EXdlnActiveTIME REMAININ1902:41:17Which component is missing from the researcher'sprocess?A researcher is comparing three new formulas for grasskiller. To conduct the experiment, the researcherpurchases 30 pieces of sod from various vendors to usein the study. To create the three treatment groups, theresearcher numbers the pieces of sod 1-30 and placesthe numbers in a hat. The researcher randomly selectsO The researcher did not use randomization whenassigning the groups.O The researcher should not have purchased sod fromdifferent vendors.10 numbers, making sure to mix the numbers betweeneach selection, and then repeats that process one moretime to select the pieces of sod in the experiment.O The researcher did not assign the chosen pieces ofsod to treatment groups.O The researcher should have randomly selected 10numbers a total of three times.SubritNextSave and ExitMark this and return

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Answered: Which component is missing from the…

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter5: A Survey Of Other Common Functions

Section5.6: Higher-degree Polynomials And Rational Functions

Problem 5E: Population Genetics In the study of population genetics, an important measure of inbreeding is the...

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Population Genetics In the study of population genetics, an important measure of inbreeding is the proportion of homozygous genotypesthat is, instances in which the two alleles carried at a particular site on an individuals chromosomes are both the same. For population in which blood-related individual mate, them is a higher than expected frequency of homozygous individuals. Examples of such populations include endangered or rare species, selectively bred breeds, and isolated populations. in general. the frequency of homozygous children from mating of blood-related parents is greater than that for children from unrelated parents Measured over a large number of generations, the proportion of heterozygous genotypesthat is, nonhomozygous genotypeschanges by a constant factor 1 from generation to generation. The factor 1 is a number between 0 and 1. If 1=0.75, for example then the proportion of heterozygous individuals in the population decreases by 25 in each generation In this case, after 10 generations, the proportion of heterozygous individuals in the population decreases by 94.37, since 0.7510=0.0563, or 5.63. In other words, 94.37 of the population is homozygous. For specific types of matings, the proportion of heterozygous genotypes can be related to that of previous generations and is found from an equation. For mating between siblings 1 can be determined as the largest value of for which 2=12+14. This equation comes from carefully accounting for the genotypes for the present generation the 2 term in terms of those previous two generations represented by for the parents generation and by the constant term of the grandparents generation. a Find both solutions to the quadratic equation above and identify which is 1 use a horizontal span of 1 to 1 in this exercise and the following exercise. b After 5 generations, what proportion of the population will be homozygous? c After 20 generations, what proportion of the population will be homozygous?
Forming an Experimental Group To conduct an experiment, researchers randomly select five students from a class of 20. How many different groups of five students are possible?
Could You Help Me With The Answer For This Question? A study was conducted by researchers to determine if application of duct tape is more effective than cryotherapy (liquid nitrogen applied to the wart for 10 seconds every 2 to 3 weeks) in the treatment of common warts. The researchers randomly divided 40 patients into two groups. The 20 patients Group 1 had their warts treated by applying duct tape to the wart for 6.5 days and then removing the tape for 12 hours, at which point the cycle was repeated, for a maximum of 2 months. The 20 patients in group 2 had their warts treated by cryotherapy for a maximum of six treatments. Once the treatments were complete, it was determined that 17 patients in Group 1 (duct tape) and 11 patients in Group 2 (cryotherapy) had complete resolution of their warts. (Source: Archives of Pediatrics and Adolescent Medicine, 156(10), 2002) Conduct a hypothesis test to address the research question whether application of duct tape is more effective than…

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