Which of the following combinations of quantum numbers are allowed for an electron in a one-electron atom? A)  n = 7 , l = 5 , m = -2 , ms = +1B)  n = 3 , l = 1 , m = 0 , ms = -½c)  n = 4 , l = -4 , m = -5 , ms = 0D) n = 6 , l = 3 , m = 0 , ms = -½

Question
Asked Apr 4, 2019
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Which of the following combinations of quantum numbers are allowed for an electron in a one-electron atom?
 
A)  n = 7 , l = 5 , m = -2 , ms = +1
B)  n = 3 , l = 1 , m = 0 , ms = -½
c)  n = 4 , l = -4 , m = -5 , ms = 0
D) n = 6 , l = 3 , m = 0 , ms = -½
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Expert Answer

Step 1

Principal quantum number is represented by n and values of n must be integers (1,2,3…)

When principal quantum number is n, then azimuthal  quantum number (l) is from 0 to (n-1)

The values of magnetic quantum number (ml) are –l to +l.

Spin quantum number (ms) is always +1/2 or +1/2.

Step 2

(A)  When n=7, the values of l are 0, 1, 2, 3, 4, 5, 6 and the values of ml are (-6, -5, -4…4, 5, 6). ms = +1 is not possible since it should be either +1/2 or +1/2. Hence, this combination is not allowed.

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Step 3

(B)  When n=3, the values of l are 0, 1, 2 and the values of ml are (-2,-1, 0, 1, 2). The given value of ms...

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