College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Which of the following statements are true of converging lenses? Identify all that apply.
- Converging lenses are thicker at the center than they are at the edges.
- If the bottom half of a converging lens is covered, then the top half of the image will not be visible.
- Converging lenses only produce real images.
- Converging lenses can produce images which are both magnified and reduced in size.
- Converging lenses only produce inverted images.
- Converging lenses have a + focal length.
- The images formed by a converging lens can be located on either side of the lens relative to the object.
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- From where you stand one night, you see the moon directly over a nearby streetlamp. You use a converging lens to get the moon’s image sharply focused on a card; when you do so, the image of the lamp is a little out of focus. To bring the lamp’s image into sharp focus, do you need to move the card closer to the lens or farther from the lens?arrow_forwardA converging lens is placed 38.0 cm to the right of a diverging lens of focal length 15.0 cm. A beam of parallel light enters the diverging lens from the left, and the beam is again parallel when it emerges from the converging lens. Calculate the focal length of the converging lens. f = cmarrow_forward30. A pebble 1 cm tall is placed 40 cm to the left of a +5-diopter lens. A –5-diopter lens is placed 30 cm to the right of the first lens. Where will the final image be located, and will it be real or virtual? What will be the size of the final image, and will it be erect or inverted? ** P = +5 D P2 = -5 D 1 cm 40 cm- 30 cm-arrow_forward
- You place a converging lens between the light source and the screen. If the distance between the light source and the screen is 1 m and an image is formed on the screen when the lens if 0.2 m from the light source, determine the second position of the lens that will also produce an image on the screen.arrow_forwardThe object-lens distance for a certain converging lens is 400mm. The image is three times the size of the object. To make the image five times the size of the object-lens distance must be changed to: 600 mm 360 mm 540 mm 960 mm 720 mmarrow_forwardWhich of the following statements if true for a refracting telescope? The eyepiece is a diverging lens. The final image is real. The image formed by the objective is virtual. The purpose of a telescope is to view small nearby objects. The intermediate image is formed at a focal point of an objective. The objective is a diverging lens.arrow_forward
- If a single lens forms a virtual image of an object, then Group of answer choices The image must be inverted. The lens could be either a diverging or a converging lens. The lens must be a diverging lens. The lens must be a converging lens.arrow_forwardChoose the correct statement regarding a telescope being used to look at Venus. If the focal distance of the objective lens is lengthened, then its magnification decreases. The eyepiece lens forms a real image of Venus. The image of Venus formed by the objective lens is located inside its focal point. The converging objective lens forms a virtual image of Venus. The image formed by the objective lens should be located just outside the focal point of the eyepiece lens.arrow_forwardAn object is placed 40 cm in front of a converging lens that has a 60-cm focal length. Where will the image be formed? Select answer from the options below 24 cm in front of the lens 120 cm in front of the lens None of the choices are correct. 120 cm behind the lens 24 cm behind the lensarrow_forward
- Are the below statements about this image true or false? The lens in the image has a negative magnification. The image produced by the lens has a negative distance. If you put a screen at the focal plane of the lens, you would see the light create a diffraction pattern. It is possible that the lens in the image is just a sinlge thin lens. The lens only refracts visible light. Dispersion in the lens would make different colors of light focus at different locations.arrow_forwardA diverging lens with focal length |f = 18.0 cm produces an image with a magnification of +0.620. What are the object and image distances? (Include the sign of the value in your answers.) cm cm object distance image distancearrow_forwardActivity 1. Use ray diagrams to find the image position and magnification for an object at each of the following distances from a converging lens with a focal length of 20 cm: (a) 20 cm; (b) 15 cm; 2. A beam of parallel rays spreads out after passing through a thin diverging lens, as if the rays all came from a point 40.0 cm from the center of the lens. You want to use this lens to form an erect, virtual image that is the 1/3 height of the object. (a) Where should the object be placed? Where will the image be? (b) Draw a principal- ray diagram.arrow_forward
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