Which statements are not valid for a projectile? Take up as positive. Check all that apply. The projectile has the same velocity at arny point on its path. The acceleration of the projectile is positive and decreasing when the projectile is moving upwards, zero at the top, and increasingly negative as the projectile descends. The acceleration of the projectile is a constant negative value. The y component of the velocity of the projectile is zero at the highest point of the projectile's path The velocity at the highest point is zero

Which statements are not valid for a projectile? Take up as positive. Check all that apply. The projectile has the same velocity at arny point on its path. The acceleration of the projectile is positive and decreasing when the projectile is moving upwards, zero at the top, and increasingly negative as the projectile descends. The acceleration of the projectile is a constant negative value. The y component of the velocity of the projectile is zero at the highest point of the projectile's path The velocity at the highest point is zero

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter4: Motion In Two And Three Dimensions

Section: Chapter Questions

Problem 8CQ: Answer the following questions for projectile motion on level ground assuming negligible air...

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Which statements are not valid for a projectile? Take up aspositive.(a) The projectile has the same x velocity at any point onits path.(b) The acceleration of the projectile is positive anddecreasing when the projectile is moving upwards,zero at the top, and increasingly negative as theprojectile descends.(c) The acceleration of the projectile is a constant negativevalue.(d) The y component of the velocity of the projectile iszero at the highest point of the projectile’s path.(e) The velocity at the highest point is zero.
Consider a projectile launched form ground level at an angle of elevation with an initial velocity . The maximum horizontal range is given by xmax=(v 2/0 sin2θ)/g, where g is the acceleration due to gravity. Here is the problem: If a soccer ball is kicked from ground level with an initial velocity of 28 m/sec, what is the smallest positive angle at which the player should kick the ball to reach a teammate 48m down the field? Assume that the ball reaches the teammate at ground level on the fly. Round to the nearest tenth of a degree.
You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this statement, consider a ball thrown off the top of a building with a velocity v at an angle ? with respect to the horizontal. Let the building be 54.0 m tall, the initial horizontal velocity be 8.60 m/s, and the initial vertical velocity be 12.5 m/s. Choose your coordinates such that the positive y-axis is upward, and the x-axis is to the right, and the origin is at the point where the ball is released. (a) With these choices, find the ball's maximum height above the ground and the time it takes to reach the maximum height. maximum height above ground m time to reach maximum height s (b) Repeat your calculations choosing the origin at the base of the building. maximum height above ground m time to reach maximum height s
A projectile is launched with a launch angle of 30° with respect to the horizontal direction and with an initial speed of 26 m/s. How do the vertical and horizontal components of the projectile's velocity vary with time?The initial velocity in the x-direction vx0 is related to the initial speed by vx0 = v0 cos 30°. The constant velocity in the x-direction means that the equation describing the time dependence of x for the particle, with x0 taken as 0, is x = x0 + vx0t = 0 + m/s t. The equation for the vertical coordinate, which is constantly accelerating downward at g = 9.8 m/s2, is y = y0 + vy0t − 1 2 gt2 = m/s t + m/s2 t2.
A projectile is launched with speed v at an angle of ?2 above the horizontal going to a maximum height NH=4.08 H.The projectile is then launched with the same initial speed but an angle of ?1 above the horizontal going to a maximum height H.Please derive the ratio of the total time of flight of the projectile as the time for launch at angle ?2 to that time at angle ?1.
A marble is launched from the edge of a table at a angle of 45 ° up from horizontal and goes through the air until it hits the floor. True or False? For such a marble, |vy| (the magnitude of the y-component of the velocity) is decreasing the entire time the marble is airborne. Group of answer choices
For a projectile lunched with an initial velocity of v0 at an angle of θ (between 0 and 90o) , a) derive the general expression for maximum height hmax and the horizontal range R. b) For what value of θ gives the highest maximum height? Solution The components of v0 are expressed as follows: vinitial-x = v0cos(θ) vinitial-y = v0sin(θ) a) Let us first find the time it takes for the projectile to reach the maximum height. Using: vfinal-y = vinitial-y + ayt since the y-axis velocity of the projectile at the maximum height is vfinal-y = Then, = vinitial-y + ayt Substituting the expression of vinitial-y and ay = -g, results to the following: = - t Thus, the time to reach the maximum height is tmax-height = / We will use this time to the equation yfinal - yinitial = vinitial-yt + (1/2)ayt2 if we use the time taken to reach the maximum height, therefore, the displacement will yield the maximum height, so hmax = vinitial-yt + (1/2)ayt2 substituting, the vinitial-y expression above,…
In a volleyball game held in school, Player A at position X serves the ball from a height of 1.3m from the ground, imparting it with an initial velocity at an angle of 50 degrees from the horizontal, He aimed the all to land at point O, 0.5m short to Player B, thus making an ace, Incidentally the Player B is an expert in mind reading. The instant the server hits the ball, Player B started running from rest with a constant acceleration a. Check whether the ball willclear the 2.42m high net.(answer in meters)b. At what horizontal distance in meters from position Y will Player B intercept the ball, given that he intercepts it at a height of 1.6m?c. What is the acceleration in m/s^2 of Player B
Problem: For a projectile lunched with an initial velocity of v0 at an angle of θ (between 0 and 90o) , a) derive the general expression for maximum height hmax and the horizontal range R. b) For what value of θ gives the highest maximum height? Solution The components of v0 are expressed as follows: vinitial-x = v0cos(θ) vinitial-y = v0sin(θ)
From the window of a building, a ball is tossed from a height y0 above the ground with an initial velocity of 8.0 m/s and angle of 25.0° below the horizontal. It strikes the ground 4.00 s later. (a) If the base of the building is taken to be the origin of the coordinates, with upward the positive y-direction, what are the initial coordinates of the ball? (b) With the positive x-direction chosen to be out the window, find the x- and y-components of the initial velocity. (c) Find the equations for the x- and y-components of the position as functions of time. (d) How far horizontally from the base of the building does the ball strike the ground? (e) Find the height from which the ball was thrown. (f) How long does it take the ball to reach a point 0 m below the level of launching?
From the window of a building, a ball is tossed from a height y0 above the ground with an initial velocity of 8.00 m/s and angle of 20.0° below the horizontal. It strikes the ground 3.00 s later. (a) If the base of the building is taken to be the origin of the coordinates, with upward the positive y-direction, what are the initial coordinates of the ball? (b) With the positive x -direction chosen to be out the window, find the x - and y -components of the initial velocity. (c) Find the equations for the x - and y -components of the position as functions of time. (d) How far horizontally from the base of the building does the ball strike the ground? (e) Find the height from which the ball was thrown. (f) How long does it take the ball to reach a point 10.0 m below the level of launching? (answer D, E, F only)
Using the vy component of the initial velocity for a projectile projected at an angle, which of the following quantities can be determined? Choose the answer: a. time in reaching the peak b. maximum height reached c. both a and b d. neither a nor b