Which type of error can the statistician have made in the correct conclusion of this hypothesis test? (This is not an error that can be avoided.) Can we state the probability with which this error will occur? If so, state the value.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Multiparty problem....need help on last two problems g and h.

In the following two hypothesis test problems, the test statistic (z-
score) will be given. Following these is a separate problem for which
you will have to calculate the z-score using the appropriate formula.
1. Swimming at local beaches is affected by the number of bacteria in the
water. Bacteria numbers are monitored by taking water samples. In the
summer, the mean number of E.Coli bacteria in a water sample at local
beaches has usually been 97. The standard deviation is known to be
15. If this August 62 water samples from beaches around Annapolis
were analyzed and the mean number of E. Coli bacteria found to be
102, does this mean that summertime E. Coli bacteria levels have
increased? Use a significance level of 1% for this test. (Note: In part
(d), the test statistic (z-score) is GIVEN.)
а)
102
97
o =
15
n =
62
a =
0.01
b) Why is a hypothesis test based on the normal distribution justified?
(Explain. Don't be too brief and use appropriate terminology.)
The standard deviation is known therefore, the given hypothesis test
is based on normal distribution.
c) State the hypotheses in symbols:
: H=102
: ">102
d) z = 2.62 is the test-statistic for this hypothesis test. Use it to find
the p-value.
(Give the p-value to four decimal places) p value is 0.0044
e) Will H. be rejected? (Include the numbers for your decision) Reject
Но
) Write a conclusion in context. (This is the answer to the hypothesis
test. Make sure it includes context.)There is significant evidence to
support the claim that E. coli bacteria levels have increased.
g) Which type of error can the statistician have made in the correct
conclusion of this hypothesis test? (This is not an error that can be
avoided.)
h) Can we state the probability with which this error will occur? If so,
state the value.
Transcribed Image Text:In the following two hypothesis test problems, the test statistic (z- score) will be given. Following these is a separate problem for which you will have to calculate the z-score using the appropriate formula. 1. Swimming at local beaches is affected by the number of bacteria in the water. Bacteria numbers are monitored by taking water samples. In the summer, the mean number of E.Coli bacteria in a water sample at local beaches has usually been 97. The standard deviation is known to be 15. If this August 62 water samples from beaches around Annapolis were analyzed and the mean number of E. Coli bacteria found to be 102, does this mean that summertime E. Coli bacteria levels have increased? Use a significance level of 1% for this test. (Note: In part (d), the test statistic (z-score) is GIVEN.) а) 102 97 o = 15 n = 62 a = 0.01 b) Why is a hypothesis test based on the normal distribution justified? (Explain. Don't be too brief and use appropriate terminology.) The standard deviation is known therefore, the given hypothesis test is based on normal distribution. c) State the hypotheses in symbols: : H=102 : ">102 d) z = 2.62 is the test-statistic for this hypothesis test. Use it to find the p-value. (Give the p-value to four decimal places) p value is 0.0044 e) Will H. be rejected? (Include the numbers for your decision) Reject Но ) Write a conclusion in context. (This is the answer to the hypothesis test. Make sure it includes context.)There is significant evidence to support the claim that E. coli bacteria levels have increased. g) Which type of error can the statistician have made in the correct conclusion of this hypothesis test? (This is not an error that can be avoided.) h) Can we state the probability with which this error will occur? If so, state the value.
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