Which XXX and YYY correctly complete the code to find the maximum score? Choices are in the form XXX/YYY. int[] scores = {43, 24, 58, 92, 68, 72); int maxScore; maxScore- scores[e]; for (XXX) { if (num > maxScore) { YYY; int scores: num/ maxScore = num scores != 0/num = maxScore int num: scores / maxScore = num num < scores/ num - maxScore

Which XXX and YYY correctly complete the code to find the maximum score? Choices are in the form XXX/YYY. int[] scores = {43, 24, 58, 92, 68, 72); int maxScore; maxScore- scores[e]; for (XXX) { if (num > maxScore) { YYY; int scores: num/ maxScore = num scores != 0/num = maxScore int num: scores / maxScore = num num < scores/ num - maxScore

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Cells B1, C1, and D1 contain the values Seat1Row1, Seat2Row1, and Seat3Row1. If cells B1, C1, and D1 were selected, and autofill used to fill E1, F1, and G1, what would be the auto-filled values? Seat1Row2, Seat2Row2, Seat3Row2 Seat 2Row2, Seat3Row2, Seat4Row2 Seat 2Row2, Seat3Row3, Seat4Row4 Seat 1Row1, Seat2Row2, Seat3Row2
Hi! I get this error message with this code. Can you help me? # Write your solution here def who_won(game_board): # Initialize counters for each player's encircled area player1_area = 0 player2_area = 0 # Iterate through each square in the game board for i in range(len(game_board)): for j in range(len(game_board[i])): # Check if the square is encircled by player 1's game pieces if game_board[i][j] == 1: # Check if all four surrounding squares are also player 1's game pieces if (i > 0 and game_board[i-1][j] == 1) and (i < len(game_board)-1 and game_board[i+1][j] == 1) and (j > 0 and game_board[i][j-1] == 1) and (j < len(game_board[i])-1 and game_board[i][j+1] == 1): player1_area += 1 # Check if the square is encircled by player 2's game pieces elif game_board[i][j] == 2: # Check if all four surrounding squares are also player…
7) What is the value of r after the following code executes? mySet (2, 3, 5, 7, 11) yourSet = (5, 7, 2, 11, 3) r = yourSet == mySet a. (5,7,2, 11, 3) b. [2, 3, 5, 7, 11) c. True d. error 13) How can the following algorithm be described? position = 0 while position < len(lyst): if target == lyst[position]: return position position += 1 return -1 a. sequential search b. bubble sort c. binary search d. selection sort
You are given a 2 by n grid, where the cell on row i column j contains a non-negative number ai,j . You can start at either cell in the lefttmost column, and your goal is to reach either cell in the rightmost column by a sequence of moves. You can move to an adjacent cell (if it exists) in each of the 4 cardinal directions (up,down, left and right). A path achieves a score equal to the sum of values in its cells. Note that a cell which is used twice in a path only counts its value once to the score of that path.Design an algorithm which runs in O(n) time and finds a path of minimum score from the leftmost column to the rightmost column.
True or false set{(x,x2):x∈Z}canbeseeasafunctionZ→Q. set{(x2,x):x∈Z}canbeseeasafunctionZ→Q.
1. def f(x):"""Evaluates function `f(x) = x^2 - 15 \sin(x * \pi/3)`Parameters----------x : array_likeInput(s) to the functionReturns-------out : ndarrayFunction `f`, evaluated at point(s) x"""# your code here 2. def grad_f(x):"""Evaluates gradient of a function `f(x) = x^2 - 15 \sin(x * \pi/3)`Parameters----------x : array_likePoint(s) at which gradient should be avalueatedReturns-------out : ndarrayGradient of the function `f` evaluaed at point(s) x"""# your code here # TEST 1. f(x)assert f(0.) == 0.assert np.allclose(f(np.array([2.5, 7.5])), np.array([-1.25, 41.25])) assert np.allclose(f(np.arange(-10, 10, 1)), np.arange(-10, 10, 1)**2 - 15*np.sin(np.pi/3*np.arange(-10, 10, 1)))x_min = 1.33668375assert np.allclose(f(x_min), -12.9944407) # TEST 2. grad_f(x)assert np.allclose(grad_f(0.), -15.7079)assert isinstance(grad_f(0.), float) assert np.allclose(grad_f(0), - 5*np.pi*np.cos(0)), 'Gradient at point 0 is wrong'assert np.allclose(grad_f(np.arange(-10, 10, 1)), 2*np.arange(-10,…
37. If we already #include <cstdlib> at the include section of a program, what will be the expression that will give a random integer between -10 and 10? Group of answer choices (rand( ) % 21) - 10; (rand( ) % 10) - 10; (rand( ) % 10) ; (rand( ) % 21) + 10; (rand( ) % 20) - 10;
INT_MIN = -32767 def cut_rod(price): """ Returns the best obtainable price for a rod of length n and price[] as prices of different pieces """ n = len(price) val = [0]*(n+1) # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val return val[n] # Driver program to test above functionsarr = [1, 5, 8, 9, 10, 17, 17, 20].
Q1.nq. Given a 2d grid map of '1's (land) and '0's (water),count the number of islands.An island is surrounded by water and is formed byconnecting adjacent lands horizontally or vertically.You may assume all four edges of the grid are all surrounded by water. Example 1: 11110110101100000000Answer: 1 Example 2: 11000110000010000011Answer: 3""" def num_islands(grid): count = 0 for i in range(len(grid)): for j, col in enumerate(grid[i]): if col == 1: dfs(grid, i, j) count += 1 Please code it. .
Mastermind is a code-breaking game for two players. In the original real-world game, one player A selects 4 pegs out of 6 colors and puts them in a certain fixed order; multiples of colors are possible (for example, red-green red-green). His opponent B does not know the colors or order but has to find out the secret code. To do so, B makes a series of guesses, each evaluated by the first player. A guess consists of an ordered set of colors which B believes is the code. The first player A evaluates the guess and feeds back to B how many positions and colors are correct. A position is correct ("black") if the guess and the secret code have the same color. Additional colors are correct ("white"), if they are in the guess and the code, but not at the same location. For example1 2 3 4secret: red-green red greenguess: red blue green purpleresults in one correct position ("black = 1") for the red peg at position one and one additional correct color ("white=1") for the green peg in the guess.…
Mastermind is a code-breaking game for two players. In the original real-world game, one player A selects 4 pegs out of 6 colors and puts them in a certain fixed order; multiples of colors are possible (for example, red-green red-green). His opponent B does not know the colors or order but has to find out the secret code. To do so, B makes a series of guesses, each evaluated by the first player. A guess consists of an ordered set of colors which B believes is the code. The first player A evaluates the guess and feeds back to B how many positions and colors are correct. A position is correct ("black") if the guess and the secret code have the same color. Additional colors are correct ("white"), if they are in the guess and the code, but not at the same location. For example1 2 3 4secret: red-green red greenguess: red blue green purpleresults in one correct position ("black = 1") for the red peg at position one and one additional correct color ("white=1") for the green peg in the guess.…
briefly comment the code#include <stdio.h>#include <stdlib.h>/* ADJACENCY MATRIX int source,V,E,time,visited[20],G[20][20];void DFS(int i){int j;visited[i]=1;printf(" %d->",i+1);for(j=0;j<V;j++){if(G[i][j]==1&&visited[j]==0)DFS(j);}}int main(){int i,j,v1,v2;printf("\t\t\tGraphs\n");printf("Enter the no of edges:");scanf("%d",&E);printf("Enter the no of vertices:");scanf("%d",&V);for(i=0;i<V;i++){for(j=0;j<V;j++)G[i][j]=0;}/* creating edges :P */for(i=0;i<E;i++){printf("Enter the edges (format: V1 V2) : ");scanf("%d%d",&v1,&v2);G[v1-1][v2-1]=1; } for(i=0;i<V;i++){for(j=0;j<V;j++)printf(" %d ",G[i][j]);printf("\n");}printf("Enter the source: ");scanf("%d",&source);DFS(source-1);return 0;}