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Why does the area get changed to .4 when that actualy area is 4m2? it is at the end of the equation.... d=v/a but under area it is .4... why not 4

Why does the area get changed to .4 when that actualy area is 4m2? it is at the end of the equation.... d=v/a but under area it is .4... why not 4

University Physics Volume 1
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter14: Fluid Mechanics
Section: Chapter Questions
Problem 69P: What is density of a woman floats in fresh water with 4.00% of her volume above the surface? (This...
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Why does the area get changed to .4 when that actualy area is 4m2?

it is at the end of the equation....

d=v/a

but under area it is .4... why not 4

 

thanks 

Given: A boat (with a flat bottom) and its cargo weigh 5,000 N. The area of the boat's bottom is 4 m?. Concept Used: The depth of the bottom of the boat can be calculated using the following formula: d =% Where d= Depth, V = Volume, A = Area Volume of the boat inside the water is equal to the volume of water displaced. Therefore, the volume of water displaced can be calculated as follows: V = W Where V = Volume of water displaced W = Total weight of boat and cargo D = Density of water g = Gravity
Transcribed Image Text:Given: A boat (with a flat bottom) and its cargo weigh 5,000 N. The area of the boat's bottom is 4 m?. Concept Used: The depth of the bottom of the boat can be calculated using the following formula: d =% Where d= Depth, V = Volume, A = Area Volume of the boat inside the water is equal to the volume of water displaced. Therefore, the volume of water displaced can be calculated as follows: V = W Where V = Volume of water displaced W = Total weight of boat and cargo D = Density of water g = Gravity
Calculation: As per the given problem, W = 5000 N D = 1000 kg/m g = 9.8 mls A = 4 m? Substituting the values of W, D and g in the following formula, we get V V = S000 1000x9.8 = V = 0.51 m Substituting the value of V and A in the following formula, we get d = % 051 d = 0.4 > d= 1.275 m Conclusion: The depth of the bottom of the boat = 1.275 m.
Transcribed Image Text:Calculation: As per the given problem, W = 5000 N D = 1000 kg/m g = 9.8 mls A = 4 m? Substituting the values of W, D and g in the following formula, we get V V = S000 1000x9.8 = V = 0.51 m Substituting the value of V and A in the following formula, we get d = % 051 d = 0.4 > d= 1.275 m Conclusion: The depth of the bottom of the boat = 1.275 m.
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