Work Wis done on The engine does work Weng the heat pump. Hot reservoir Hot reservoir at T/ at Tj Energy IQf is expelled to the hot Energy QA enters the engine reservoir W eng Heat Heat engine pump Energy Qd Energy IQd leaves the is drawn from the engine Cold reservoir cold Cold reservoir at Te at Te reservoir

Work Wis done on The engine does work Weng the heat pump. Hot reservoir Hot reservoir at T/ at Tj Energy IQf is expelled to the hot Energy QA enters the engine reservoir W eng Heat Heat engine pump Energy Qd Energy IQd leaves the is drawn from the engine Cold reservoir cold Cold reservoir at Te at Te reservoir

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter4: The Second Law Of Thermodynamics

Section: Chapter Questions

Problem 4.6CYU: Check Your Understanding A quantity of heat Q is absorbed from a reservoir at a temperature Th by a...

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Check your Understanding Show that QhQh=QcQc for the hypothetical engine of Figure 4.10 The second property to be demonstrated is that all reversible engines operating between the same two reservoirs have the same efficiency. To this, stat with the two engines D and E of Figure 4.10 (a), which are operating between two common heat reservoirs at temperatures Th and Tc . First, assume that D is a reversible engine and that E is a hypothetical irreversible engine that has a higher efficiency than D. If both engines perform the same amount of work W per cycle, it follows from Equation 4.2 that QhQh . It then follows from the first law that QcQc . Figure 4.10 (a) Two uncoupled engines D and E working between the same reservoirs. (b) The engines, With D working reverse. Suppose the cycle of D is so that it operates as a refrigerator, and the two engines are coupled such that the work output of E is used to drive D, as shown in Figure 4.10(b). Since QhQh and QcQc , the net result of each cycle is equivalent to a spontaneous transfer of heat from the cold reservoir to the hot reservoir, a process second law does not allow. The original assumption must therefore be wrong, and it is impossible to construct an irreversible engine such that E is more efficient than the reversible engine D. Now it is quite easy to demonstrate that the efficiencies of all reversible engines operating between the same reservoirs are equal. Suppose that D and E are reversible engines. If they are as shown in Figure 4.10(b), the efficiency of E cannot be greater than the efficiency of D, or second law would violated. If both engines are then reversed, the same reasoning implies that the efficiency of D cannot be greater than the efficiency of E. Combining these results leads to the conclusion that all reversible engines working between same two reservoirs have the same efficiency.
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