Write the equivalent infix expression for the following postfix expressions.a. x y * z + t -b. x y z + * w u / - c. x y - z u / * t s + -d. x y z w + - *
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Write the equivalent infix expression for the following postfix expressions.
a. x y * z + t -
b. x y z + * w u / -
c. x y - z u / * t s + -
d. x y z w + - *
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- Change the following infix expression to a postfix expression A*B+C*D (A+B)*(C–D) ((A+B)*C)–D A+B*(C–D/(E+F))Convert the following infix expressions to postfix notations: a. x + y + z - w / tb. x - (y + z) * w + (t - u) /sc. ((x + y) / z * (u - v)) / t + wd. x / y / z + (u * v * t) / w - swrite a c++ program that creates all 4-digit combinations from 1 - 7 for example, the first combination should be 1 2 3 4... but instead of numbers, the output should be letters. for 1 = a, 2 = b, 3 = c, 4 = d, 5 = e, 6 = f, 7 = g and the output for 1 2 3 4 should be a b c d the output for 2 3 4 5 should be b c d e
- Convert the following infix expressions to postfix notations. (A + B) + (C + D) * E A - (B + C) * D + E / F ((A + B) / (C - D) + E) * F - G A + B * (C + D) - E / F * G + HWhat is the postfix notation of the following expression, (A +B*(C-D)/E)*((F+H)*G-W*X)2. Given a boolean expression below, find the value of the expression if the values of P = 1, Q = 0, R = 1. Y = P.Q + Q.(R+P+Q)
- Write a C program to print the following pattern:**A**B*B**C*C*C**D*D*D*D**E*E*E*E*E*E… till n lineswhere n is the input and it can’t be more than 27.What is the postfix form of the expression ((x + y) 2) + ((x - 4)/3)Write a C++ program that reads in two integers, and then outputs whether the first number is greater than the second, the first number is less than the second, or the two numbers are equal. See the examples for the correct format of the output. For example: Input Result 3 5 3 is less than 5 6 1 6 is greater than 1 -42 -42 -42 is equal to -42
- Convert the following infix expression into postfix notation. (A*B+(C/D))-F (A+B)*C/ A*B+(C/D)Implement the following Boolean expressions as they are stated: (a) X = ABC + AB + AC (b) X = AB(C + DE)Here is the Python code for our Truth Table Generator function truthTable() which takes two parameters: A Boolean expression: e.g. A AND NOT (B OR C) The number of inputs: either 2, 3 or 4: A, B, C and DMain.py def truthTable(expression,inputs=2): print("Boolean Expression:") print(" X = " + expression.upper()) expression = expression.lower() #replace Boolean Operators with bitwise operators expression = expression.replace("and","&") expression = expression.replace("xor","^") expression = expression.replace("or","|") expression = expression.replace("not","~") print("\nTruth Table:") if inputs==2: print(" -------------") print(" | A | B | X |") print(" -------------") for a in range(0,2): for b in range(0,2): x = eval(expression) print(" | " + str(a) + " | " + str(b) + " | " + str(x) + " |" ) print(" -------------") elif inputs==3: print(" -----------------") print(" | A | B | C | X |") print("…