Write the rate law for a mechanism with a slow second step.Close ProblemA kinetic study is done to investigate the following reaction:2 NO2Cl2 NO2 + Cl2A proposed mechanism is:Step 1.        NO2ClNO2 + Cl    fast in both directionsStep 2.        NO2Cl + ClNO2 + Cl2    slow(a)   Does this mechanism account for the overall reaction? _____ (Yes or No)(b)   What experimental rate law would be observed if this mechanism is correct?Complete the rate law in the box below. Do not use reaction intermediates and remember that a superscript '1' is not written.Rate =  _________

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Asked Sep 16, 2019
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Write the rate law for a mechanism with a slow second step.
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A kinetic study is done to investigate the following reaction:2 NO2Cl2 NO2 + Cl2A proposed mechanism is:
Step 1.         NO2ClNO2 + Cl     fast in both directions
Step 2.         NO2Cl + ClNO2 + Cl2     slow


(a)   Does this mechanism account for the overall reaction? _____ (Yes or No)

(b)   What experimental rate law would be observed if this mechanism is correct?

Complete the rate law in the box below. 
Do not use reaction intermediates and remember that a superscript '1' is not written.

Rate =   _________
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Expert Answer

Step 1

The given reaction and mechanism are :

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2 NO2Cl >NO2 Cl2 NO2Cl NO2 Cl Step 1 fast in both directions NO2 Cl2 Step 2 NO2ClCl slow

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Step 2

(a) Yes, the given mechanism account for the overall reaction.

The proposed mechanism is :

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Step 1 NO2CI- >NO2 Cl NO2 Cl2 Step 2 NO2CI Cl Adding stepl and 2: 2 NO2CI er- NO2 C2CX Overall 2 NO2CI NO2 C2

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Step 3

(b) Let us write the mechanisms...

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Step 1 ki >NO2 + Cl k2 NO2CI fast in both directions Step 2 k3 NO2 Cl2 slow NO2ClCl

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