x= 99; if (x++ < 100 ) t <<" it's true \n "; cout www else cout t <<" it's false ";
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Max Function
Statistical function is of many categories. One of them is a MAX function. The MAX function returns the largest value from the list of arguments passed to it. MAX function always ignores the empty cells when performing the calculation.
Power Function
A power function is a type of single-term function. Its definition states that it is a variable containing a base value raised to a constant value acting as an exponent. This variable may also have a coefficient. For instance, the area of a circle can be given as:
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- .c## Write a Console Application that reads two integers, determines whether the first is a multiple of the second and displays the result. [Hint: Use the remainder operator.]Find the errors in this code: double gpa[] = {2.2, 3.8, 4.0, 3.6, 1.7, 2.8}; int countSuper = 0; // number of students whose GPA >= 3.5 for (int count = 0; count < 6; count++){ if(gpa[count] >= 3.5){ System.out.print(”\n You are super!”); } countSuper++; } System.out.print(”\n Number of super students is: ”+ countSuper);Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to pointsDistance. The calculation is:Distance = SquareRootOf( (x2 - x1)2 + (y2 - y1)2 ) #include <stdio.h>#include <math.h> int main(void) { double x1; double y1; double x2; double y2; double xDist; double yDist; double pointsDistance; xDist = 0.0; yDist = 0.0; pointsDistance = 0.0; scanf("%lf", &x1); scanf("%lf", &y1); scanf("%lf", &x2); scanf("%lf", &y2); /* Your solution goes here */ printf("%lf\n", pointsDistance); return 0;
- int a = 9; int c = 6; int d = 6; boolean m; if (a==c && c != d) { m = true}; What is the value of m? True False 6 9int y = !(12 < 5 || 3 <= 5 && 3 > x) ? 7 : 9 Based on the code above, what is the value of y if x = 1?Mortgage bond L, interest rate r =15%. The fixed payments P to pay off the loan over N years is given by P= rL(1+r/12)^12N/12(1+r/12)^12N -1) a)Write a code to compute and print P if N = 20 and the bond is $50,000 b) how P changes with N . Can you find a value for which the payment is less than $625? c) go back to N =20 and examine for different interest rate . Raising the interest rate increase the payment by $37?
- If the new operator cannot allocate the amount of memory requested, it throws_____________Print "user_num1 is negative." if user_num1 is less than 0. End with newline. Assign user_num2 with 3 if user_num2 is greater than 13. Otherwise, print "user_num2 is less than or equal to 13.". End with newline.Programming in C#: Write a console-based application that displays every perfect number from 1 through 10000. A number is perfect if it equals the sum of all the smaller positive integers that divide evenly into it. For example, 6 is perfect because 1, 2, and 3 divide evenly into it and their sum is 6. Use format strings(field size 8, right alignment) to show all perfect numbers. Display the results as seen below. 6 28 496 8128
- int fun(int k){ return ( ); void main(){ int n; cin >> n; n = n * fun(n); <-- 1 Fill in the appropriate statement and expression in fun, so that when it is called in main, and after the execution of the statement marked 1, the value of n would always be n3.int main() { int i, salary[10], range[9]={0, 0, 0, 0, 0, 0, 0, 0, 0}; double gross[10], total[10]; string amount[9]={"$200 - $299", "$300 - $399", "$400 - $499", "$500 - $599", "$600 - $699", "$700 - $799", "$800 - $899", "$900 - $999", "$1000 and over"}; for (i=0; i<10; i++){ cout<<"Please enter gross sales of salespeople "<<i+1<<": "; cin>>gross[i]; total[i]=200+(gross[i]*0.09); salary[i]=total[i]; if (salary[i]>=200 && salary[i]<=299) range[0]=range[0]+1; else if (salary[i]>=300 && salary[i]<=399) range[1]=range[1]+1; else if (salary[i]>=400 && salary[i]<=499) range[2]=range[2]+1; else if (salary[i]>=500 && salary[i]<=599) range[3]=range[3]+1; else if (salary[i]>=600 && salary[i]<=699) range[4]=range[4]+1; else if (salary[i]>=700 && salary[i]<=799) range[5]=range[5]+1; else if (salary[i]>=800 && salary[i]<=899) range[6]=range[6]+1; else if (salary[i]>=900…Programming Exercise 10 in Chapter 6 asks you find the mean and standard deviation of five numbers. Extend this programming exercise to find the mean and standard deviation of up to 100 numbers. Suppose that the mean (average) of n numbers x1, x2, . . ., xn is x. Then the standard deviation of these numbers is:S=sqrt(((x1-x)^2+(x2-x)^2+...+(xi-x)^2+...+(xn-x)^2)/n)