X Cut4 CropOOOA- / Outline自CopyPasteResizeFill-Select29 BrushesSizeColorColorRotate -21ClipboardToolsImageShapesColors2003001004000.500600700800A source generates three symbols with probability 0.25, 0.25, 0.50 at arate of 3000 symbols per second. Assuming independent generation ofsymbols, the most efficient source encoder would have average bit rate of(a) 6000 bits/sec(b)4500 bits/sec(c) 3000 bits/sec(d) 1500 bits/sec

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Asked Dec 22, 2019
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A source generates three symbols with probability 0.25, 0.25, 0.50 at a
rate of 3000 symbols per second. Assuming independent generation of
symbols, the most efficient source encoder would have average bit rate of
(a) 6000 bits/sec
(b)4500 bits/sec
(c) 3000 bits/sec
(d) 1500 bits/sec
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X Cut 4 Crop OOOA - / Outline 自Copy Paste Resize Fill- Select 29 Brushes Size Color Color Rotate - 21 Clipboard Tools Image Shapes Colors 200 300 100 400 0. 500 600 700 800 A source generates three symbols with probability 0.25, 0.25, 0.50 at a rate of 3000 symbols per second. Assuming independent generation of symbols, the most efficient source encoder would have average bit rate of (a) 6000 bits/sec (b)4500 bits/sec (c) 3000 bits/sec (d) 1500 bits/sec

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Step 1

The average bit rate of the most efficient encoder can be expressed as

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R=rxH --->(1) r = Symbol rate of source H = Information entropy

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Step 2

In this case, the probabilities of the three symbols generated by the source is 0.25, 0.25 and 0.5 respectively. The source generates symbols at a rate of 3000 symbols per second.

Step 3

Entropy is defined as the rate at which the information is being produced by the data source. Mathematically it can be e...

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• (2) H =Ep,log,(p,)–-->(2) i=1 P, = Probability of the ih symbol n= Total number of symbols

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