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X y Z 52 124 79 69 137 83 For Table 2, determine the confidence intervals of: 1. The mathematical expectation. 2. The variance. 3. The variation of the input quantity. Table values: a = 0.05 T(a/2, v= 1) = 12.7062 T(a/2, v= 2) = 4.3027 T(a/2, v= 3) = 3.1825 T(a/2, v= 4) = 2.7765 T(a/2, v= 8) = 2.3060 F(a/2, 2, 2) = 39.0000 F(a/2, 3, 3) 15.4392 = F(a/2, 4, 4) = 9.6045 | 4236 93 39 134 67 F(a/2, 2, 3) = 16.0441 F(a/2, 6, 2) = 39.3315 F(a/2, 4, 3) = 9.12 G(a, 3, 4) = 0.7574 x12=x2(a2,4)= 0.4844 x22 x 2 (1-a2, 4) = 11.1433 T(a, 5) = 1.92 33 133 95

X y Z 52 124 79 69 137 83 For Table 2, determine the confidence intervals of: 1. The mathematical expectation. 2. The variance. 3. The variation of the input quantity. Table values: a = 0.05 T(a/2, v= 1) = 12.7062 T(a/2, v= 2) = 4.3027 T(a/2, v= 3) = 3.1825 T(a/2, v= 4) = 2.7765 T(a/2, v= 8) = 2.3060 F(a/2, 2, 2) = 39.0000 F(a/2, 3, 3) 15.4392 = F(a/2, 4, 4) = 9.6045 | 4236 93 39 134 67 F(a/2, 2, 3) = 16.0441 F(a/2, 6, 2) = 39.3315 F(a/2, 4, 3) = 9.12 G(a, 3, 4) = 0.7574 x12=x2(a2,4)= 0.4844 x22 x 2 (1-a2, 4) = 11.1433 T(a, 5) = 1.92 33 133 95

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 52E
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For Table 2, determine the confidence intervals of:

  1. The mathematical expectation.
  2. The variance.
  3. The variation of the input quantity.

table 2 and the tablic values are in the images below

X y Z 52 124 79 69 137 83 46 126 93 39 134 67 33 133 95
Transcribed Image Text:X y Z 52 124 79 69 137 83 46 126 93 39 134 67 33 133 95
Table 2 X V Z 52 124 79 69 137 83 For Table 2, determine the confidence intervals of: 1. The mathematical expectation. 2. The variance. 3. The variation of the input quantity. Table values: α = 0.05 T(a/2, v= 1) = 12.7062 T(a/2, v = 2) = 4.3027 T(a/2, v= 3) = 3.1825 T(a/2, v = 4) = 2.7765 T(a/2, v = 8) = 2.3060 F(a/2, 2, 2) = 39.0000 F(a/2, 3, 3) = 15.4392 F(a/2, 4, 4) = 9.6045 46 126 93 39 134 67 F(a/2, 2, 3) = 16.0441 F(a/2, 6, 2) = 39.3315 F(a/2, 4, 3) = 9.12 G(a, 3, 4) = 0.7574 x12= x2(a2, 4) = 0.4844 x22=X2 (1-a2, 4) = 11.1433 t(a, 5) = 1.92 33 133 95
Transcribed Image Text:Table 2 X V Z 52 124 79 69 137 83 For Table 2, determine the confidence intervals of: 1. The mathematical expectation. 2. The variance. 3. The variation of the input quantity. Table values: α = 0.05 T(a/2, v= 1) = 12.7062 T(a/2, v = 2) = 4.3027 T(a/2, v= 3) = 3.1825 T(a/2, v = 4) = 2.7765 T(a/2, v = 8) = 2.3060 F(a/2, 2, 2) = 39.0000 F(a/2, 3, 3) = 15.4392 F(a/2, 4, 4) = 9.6045 46 126 93 39 134 67 F(a/2, 2, 3) = 16.0441 F(a/2, 6, 2) = 39.3315 F(a/2, 4, 3) = 9.12 G(a, 3, 4) = 0.7574 x12= x2(a2, 4) = 0.4844 x22=X2 (1-a2, 4) = 11.1433 t(a, 5) = 1.92 33 133 95
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