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Q: S 2x dx 1+x2 In|1 + x²| + c Option 2

A:

Q: 5. Evaluate: (а) ( 5х* -х-4) dx (b) f( 2x +4)(3x + 6)dx

A: 5. (a) We will evaluate the integral ∫5x2-x-4dx

Q: L(1-a) ( In =) dz 4 1 L6(1-2) ( In =) dr

A:

Q: z'dz 214

A: We have to find ∫x2 dxx3+4.

Q: S² (4-x²)³2x² dx

A: I am attaching image so that you understand each and every step.

Q: S 10) L -1. 2 s* +2s – 3 11) L-' (s – 2)(s – 3)(s – 6)J 1 12) L' 3 s° +5s,

A:

Q: S, 53-2x dx -2

A: 4 Given  ∫-22  53-2x  dx

Q: 2 cosh x +losion2x = 5

A: I am attaching image so that you understand each and every step.

Q: -2 4– x² dx -2

A: To find the value of given definite integral.

Q: Integrate S(x-4)(x²-8x+12} dx

A:

Q: 1 + cosh 2x 9. cosh² x 2

A: To prove the identity

Q: 18. Find xV4x -3 dx 18. SxV4x - 3 dx

A: Use substitution to solve

Q: Solve 5cosh(x)+1=2sinh(x).

A:

Q: 1. S(VE – Vr² + VE³) dt

A:

Q: Sólvé. |10x + 4| – 5 = 6 x = 1 Preview %3D

A:

Q: h(x)=ln(6x+4/x^5/3sinx), find h′(x).

A: Use logarithmic property then differentiate

Q: 20. [2z°e*= dz

A: According to our guidelines we can answer on three subparts, or first question and rest can be…

Q: Evaluate | x + 2x + 3 xp- Vx* +x +1 -dx

A:

Q: If ∫3 6 (5f(x)+2)dx=14, then ∫3 6 f(x)dx=

A: ∫ab fx±gx dx = ∫ab f(x)dx ± ∫ab g(x) dx

Q: Evaluate the definite integral.

A:

Q: Evaluate S (2x+3) dx x² (x²+1)

A:

Q: 5. Solve for x² − x+6 x³ + 3x 1³ dx.

A:

Q: 33. d dt 10+1

A:

Q: Integrate: S (4z° S (4x² – 3x + 1)* (8x – 3) dæ

A: Integrate above equation by substitute.

Q: Differentiate y = (x + ex)4

A:

Q: 3. fx²(9-x³)5 dx 4. J√4x-1 dx

A:

Q: x4 – 4x3 + 8x² – 13x + 13 dx - - (x – 1)(x2 + 4)

A:

Q: 4. Evaluate: - V16. dx 16 x2 -

A:

Q: 3 Evaluate: S(5x¹2x³ + 3x − 4)dx -

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Q: ller x-value) er x-value)

A:

Q: S (7z³ + 4x²) dx

A:

Q: 11-x 1 || | dydzdx 0 0 x+z

A: the given triple integral is: we have to evaluate the given triple integral.

Q: Q3. Evaluate S 2x+1-5x-1 dx 10*

A: Given that ∫2x+1-5x-110x dx evaluate the integral

Q: Find y' and y". y = x² In(9x) y' = x + 2x ln (9x) y" = 3+2 ln( 9x)

A: Given function is Differentiating with respect to x by using product rule of differentiation, we…

Q: Evaluate S((x^-4) + (4x^2) - (8/x) + 3)dx

A:

Q: X 10. [7x+3x+1 dx 2x ux 11. Jhxdx 12. f(x²-4)³ dx 2x

A:

Q: 门4(z + 1)ele+1) de

A: We will find out the required value.

Q: Evaluate [ x² V1+x' dx by using substitution method.

A: on doing integration we get

Q: solve lox t lox- =011 0.1

A:

Q: Evaluate S(4x³ + x)(4x² + 1)/2 dx.

A:

Q: أ 12, x > 1 (b) ) 5 f(x) dx

A: According to Bartleby's guideline, we can only solve three subparts of a question. Please post again…

Q: Solve for x. Sx+10 58° 11x+2 U

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Q: x4 + Vtan y = x ln y

A:

Q: 6. 2 I (ve**)dx dy у /2

A:

Q: Evaluate [², dx V4-x2 2.

A:

Q: - In x (7) S dx 5 (8) Í dx 4 4+x (9) [xV1-2x dx

A:

Q: 2s+1 1. L-1 (s+1)²,

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: 413 xdx X csc 2. (sec2/3 xcsc4/3

A:

Q: 1.ſ(8x³ − 6x² + 12x − - -9)dx

A: Solve the integration

Q: 1/2 Scave [ (a²-x² - x²) ¹²h dx (8) = √5 (9² - x²)³/²2 [³ (a²-x²) ¹1²2 0/² ] + c 15

A: Given:       ∫a2x6-x8dx Rewrite:      =∫x3a2-x2dx substitute u=a2-x2→dudx=-2x→dx=-12xdu…

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.