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x3 + 10x – y = 5 onsider the nonlinear system of equations: Taking the initial guess0) =1, y0)=1 use one step of Newton's method to approximate the x +y³ – 10y = -1 lution of the given system. Which of the following alternatives is true. s. The calculations are obtained by keeping at least 3 decimal places.

x3 + 10x – y = 5 onsider the nonlinear system of equations: Taking the initial guess0) =1, y0)=1 use one step of Newton's method to approximate the x +y³ – 10y = -1 lution of the given system. Which of the following alternatives is true. s. The calculations are obtained by keeping at least 3 decimal places.

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 17EQ
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(x3 + 10x – y =5 x+y3 – 10y = - 1 solution of the given system. Which of the following alternatives is true. Consider the nonlinear system of equations: Taking the initial guess0) =1, y) =1 use one step of Newton's method to approximate the p.s. The calculations are obtained by keeping at least 3 decimal places. Your answer: p(1). =0.53333, y1): 0.06667 x1) =5.53333, yl") = – 7.06667 2(1). =1.53333, y y(1). = -1.6667 (1) = 0.5213, y") = – 0.05051 Clear answer
Transcribed Image Text:(x3 + 10x – y =5 x+y3 – 10y = - 1 solution of the given system. Which of the following alternatives is true. Consider the nonlinear system of equations: Taking the initial guess0) =1, y) =1 use one step of Newton's method to approximate the p.s. The calculations are obtained by keeping at least 3 decimal places. Your answer: p(1). =0.53333, y1): 0.06667 x1) =5.53333, yl") = – 7.06667 2(1). =1.53333, y y(1). = -1.6667 (1) = 0.5213, y") = – 0.05051 Clear answer
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