XVx + 6 dx53.X(r +1)/2- x dx56.1- x dx55.2x + 1dxx2-1dx5857.x + 42x- 1secs 7x tan 7x dx60.cos3 2x sin 2x dx59.In ExercisesEvaluating a Definite Integral61-68, evaluate the definite integral. Use agraphing utility to verify your result.x3(2x41)2 dx61.62.02x2x3 1 dx63.x/1 - dx64.14165.dx2x + 1dx1 + 2x205167.хdx68.Vx(I+dx2х - 64

Question
Asked Dec 2, 2019
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XVx + 6 dx
53.
X
(r +1)/2- x dx
56.
1- x dx
55.
2x + 1
dx
x2-1
dx
58
57.
x + 4
2x- 1
secs 7x tan 7x dx
60.
cos3 2x sin 2x dx
59.
In Exercises
Evaluating a Definite Integral
61-68, evaluate the definite integral. Use a
graphing utility to verify your result.
x3(2x41)2 dx
61.
62.
0
2x2x3 1 dx
63.
x/1 - dx
64.
1
4
1
65.
dx
2x + 1
dx
1 + 2x2
0
5
1
67.
х
dx
68.
Vx(I+
dx
2х - 6
4
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XVx + 6 dx 53. X (r +1)/2- x dx 56. 1- x dx 55. 2x + 1 dx x2-1 dx 58 57. x + 4 2x- 1 secs 7x tan 7x dx 60. cos3 2x sin 2x dx 59. In Exercises Evaluating a Definite Integral 61-68, evaluate the definite integral. Use a graphing utility to verify your result. x3(2x41)2 dx 61. 62. 0 2x2x3 1 dx 63. x/1 - dx 64. 1 4 1 65. dx 2x + 1 dx 1 + 2x2 0 5 1 67. х dx 68. Vx(I+ dx 2х - 6 4

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Expert Answer

Step 1

The given integral is,

2
2xVxldx
1
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2 2xVxldx 1

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Step 2

Evaluate the given integral as follows.

Let ux1. Then du = 3x'dx
Also
when x 1 u 2
when x 2, u 9
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Let ux1. Then du = 3x'dx Also when x 1 u 2 when x 2, u 9

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Step 3

Therefore...

Vudu
|2x2 Vx +1dx
3
2
и'du
3
2
4
95-22)
4
(27-22)
12
9
=10.74292128
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Vudu |2x2 Vx +1dx 3 2 и'du 3 2 4 95-22) 4 (27-22) 12 9 =10.74292128

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Math

Calculus