x+y-4) dx-(3x-y-4)dy=0; when x=4, y=1 Solve using Coefficient linear in the two variables

Q: 4. (у- 2ку + 6x) dx - (x?- 2ху + 2) dy -0

A:

Q: SOLVE USING INTEGRATING FACTOR (2y² – 3x²) d x + (2x² – x y) dy = 0; y (1) = 1 9.

A: Let's find.

Q: Find the solution of the homogenous equation: 2(2x2+y2)dx-xydy=0

A: The given differential equation is  2(2x2+y2)dx -xy dy=0

Q: solve homogeneous equation by linear method 2. x(dy/dx) + y = x*sinx

A: We use linear differential equation method

Q: Find the general solution of dy -2x6 dx y-4

A:

Q: dx dt -1 -3 [:] 2 with x(0) 4 Give your solution in real form.

A:

Q: 1. Solve x² - 2x- 2 d²y dx 2 dy 4y = x² + 2logx.

A:

Q: 3. General solution of x dy = (2xe* – y + 6x²) dx

A: The given differential equation,     x dy=2xex-y+6x2dx

Q: Solve simultaneous equation dx/dt=5x-9y , dy/dt=2x-y , x=3 , y=2

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Q: find the general solution of the given equation. 3y'' - y' = 0

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Q: Solve for all possible solution in the equation y^2 + y = x + Inx + e^y - x^2, using Secant Method *

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Q: Solve 1 . Find a particular solution to a' = x – y + e', y = -4x + y +t using undetermined…

A:

Q: a) Find the general solution of the equation dªy dy dx² 4- x2 + 3e* - dr4 by using the method of…

A: As you have posted multiple parts,but they are independent so according to our guidelines we will…

Q: use Separation of Variables to find the general solution. yy' = x

A:

Q: Solve dy Зу - 4х dx x-y – 2x = C 2x* + x-3 y = C 4 x-3y – 2x-2 = C 2x2 + xy = C -3

A:

Q: Solve for all possible solution in the equation y^2 + y = x + Inx + e^y - x^2, using Secant Method

A: We have the following equation in two variables : y2 + y = x + ln(x) + ey - x2   As there are two…

Q: Solve: (2x + 3y – 5)dx + (3x – y – 2)dy = 0 . Show solution for determining the coordinates of the…

A: Find your answer below

Q: (2x2y+3y3)dx - (x3+2xy2)dy = C Solve for Particular Solution when x = 1, y = 1

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Q: Solve: 1. (1+x)dy-yds-0 2. y dr (1+x) (separation of variables)

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Q: dy -y² = yx+x² dx

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Q: Find the general solution of the lines Зу + 2 y - 2 )dx + ( 2x -+ 1 )dy = 0 4 2

A: Let us consider the given differential equation f(x,y)dx+g(x,y)dy=0 Using substitution,  x=X+hy=Y+k…

Q: 2. (D² - 3D + 2)y=1+x

A: The given differential equation is;  (D2-3D+2)y=1/(1+e-x).

Q: How do I solve this Bernoulli equation using P(x), Q(x) and n as well as u(y)?

A: First, we write it in form of Bernoulli Differential equation.

Q: x² - y² + xy dy/dx =0  What is the general solution of differantial equation

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Q: Find the general solution : (3x + 2y + 4) dx + (3x + 2y - 3) dy = 0

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Q: (x + 2y – 1) dx - ( 2x + y - 5 ) dy = 0

A:

Q: (6x -3y +2)dx - (2x– y – 1)dy = 0 (coefficients linear in two variables)

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Q: 2.Solve bernoulli (x ^ 2 + y ^ 2) * dx - xydy = 0

A:

Q: 1. y' + 2y = x²y³ .2.3

A: Given problem:- solve the given differential equation y' +2y=x2 y3

Q: Solve the equations. 1. (2x - y)dx + (4x + y- 6)dy = 0 2 (x+ y-1)dx + (2x + 2y + 1)dy = 0

A:

Q: Solve 2(ax+Y) dx + (3x +Y) dy =0 ,y) =2

A: SOLUTION-

Q: solve (3-2) dx Ex Solve 3xý = zy (y-3) Ex6 + (3x-4) dy =0 %3D

A: According to the guidelines issued by the company We are supposed to answer only one question.…

Q: What is the solution of (2x - y)dx + (4x + y– 6) dy = 0? а. (x+у-3)°- с (2х +у- 4)? b. (x-y+3)²=…

A:

Q: solve the homogenous equation . (2x-3y)dx+(2y-3x)dy=0

A:

Q: Find the Particular Solution indicated. (Homogenous Linear Equation with Constant Coeffiecients)

A: Given : Homogenous Linear Differential Equation with Constant Coefficients               D2+D-12y=0…

Q: Solve: Linear in Two Variables (2x- 3y + 6) dx - (4x - 6y +2) dy = 0

A:

Q: xydx - (x^2+3y^2)dy =0 Solve for general solution .(show complete solution)

A: Given, xy dx - (x2+3y2) dy =0

Q: What is the general solution of differantial equation?  Whicf of the options x² - y² + xy dy/dx =0

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Q: 3z (sec-(-3z?))³ 2|–3z*|-/9zª–1 If y= sec-1 (-3x²), then dy dz

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Q: Use variation of parameters to find the general solution of y′′−2y′+ 2y=(e^x)csc(x)

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Q: Solve x3y dx= (x3+y3)dy

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Q: Solve by homogeneous equations method (x² - 4xy - 2y²) dx + (y² + 4xy - 2x²) dy = 0

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Q: x In x dx Show that , V4 – x² dx = (2n + 3v3).

A: Part (a) Given integral is ∫12xlnxdx

Q: 5. (y-2)dx-(x-y-1)dy 0

A:

Q: find explicit solution: x^2 dy/dx =y-xy       y(-1)=-4

A: Given differential equation is                                       here we can easily separate the…

Q: Use variation of parameters to find a particular solution of y'' - Y = 4e-x 1-e-2x Yp (x) =

A: Solution of the differential equation, By using the method of Variation of perameters

Q: 5) SOLVE dy _ yz %3D x2

A: A differential equation is an equation in x,y and derivatives of y. An ordinary differential…

Q: Find the particular solution of (d2y/dx2) = 4x3 - 2x; y' = 4/5 and y = 1 when x = 1

A: Given differential equation, d2ydx2=4x3-2x       ...(1) y'=45 and y=1 when x=1

Q: (2х + Зу — 5)dx + (3x — у — 2)dy — 0

A:

Quadratic Equation

When it comes to the concept of polynomial equations, quadratic equations can be said to be a special case. What does solving a quadratic equation mean? We will understand the quadratics and their types once we are familiar with the polynomial equations and their types.

Demand and Supply Function

The concept of demand and supply is important for various factors. One of them is studying and evaluating the condition of an economy within a given period of time. The analysis or evaluation of the demand side factors are important for the suppliers to understand the consumer behavior. The evaluation of supply side factors is important for the consumers in order to understand that what kind of combination of goods or what kind of goods and services he or she should consume in order to maximize his utility and minimize the cost. Therefore, in microeconomics both of these concepts are extremely important in order to have an idea that what exactly is going on in the economy.