You are conducting a study to see if the proportion of women over 40 who regularly havemammograms is significantly more than 0.15. You use a significance level of a = 0.01.Но:р — 0.15H1:p > 0.15You obtain a sample of size n137 in which there are 28 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic =What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =The p-value is..less than (or equal to) agreater than aThis test statistic leads to a decision to...reject the nullaccept the nullfail to reject the nullAs such, the final conclusion is that.O There is sufficient evidence to warrant rejection of the claim that the proportion ofwomen over 40 who regularly have mammograms is more than 0.15.O There is not sufficient evidence to warrant rejection of the claim that the proportion ofwomen over 40 who regularly have mammograms is more than 0.15.The sample data support the claim that the proportion of women over 40 who regularlyhave mammograms is more than 0.15.There is not sufficient sample evidence to support the claim that the proportion ofwomen over 40 who regularly have mammograms is more than 0.15.

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Asked Dec 5, 2019
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You are conducting a study to see if the proportion of women over 40 who regularly have
mammograms is significantly more than 0.15. You use a significance level of a = 0.01.
Но:р — 0.15
H1:p > 0.15
You obtain a sample of size n
137 in which there are 28 successes.
What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =
What is the p-value for this sample? (Report answer accurate to four decimal places.)
p-value =
The p-value is..
less than (or equal to) a
greater than a
This test statistic leads to a decision to...
reject the null
accept the null
fail to reject the null
As such, the final conclusion is that.
O There is sufficient evidence to warrant rejection of the claim that the proportion of
women over 40 who regularly have mammograms is more than 0.15.
O There is not sufficient evidence to warrant rejection of the claim that the proportion of
women over 40 who regularly have mammograms is more than 0.15.
The sample data support the claim that the proportion of women over 40 who regularly
have mammograms is more than 0.15.
There is not sufficient sample evidence to support the claim that the proportion of
women over 40 who regularly have mammograms is more than 0.15.
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You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly more than 0.15. You use a significance level of a = 0.01. Но:р — 0.15 H1:p > 0.15 You obtain a sample of size n 137 in which there are 28 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is.. less than (or equal to) a greater than a This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that. O There is sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15. O There is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15. The sample data support the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15. There is not sufficient sample evidence to support the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15.

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Expert Answer

Step 1

It is given that the sample size is 137 and the number of successes is 28.

The population proportion is 0.15 and the level of significance is 0.01.

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That is, n=137 , x = 28 and p = 0.15, a= 0.01

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Step 2

The null and alternative hypotheses are given below:

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H:p=0.15 H:p> 0.15

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Step 3

The sample proportion is calculated below:

Th...

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p= 28 137 = 0.20 %3D

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Hypothesis Testing

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