You are interested in constructing a 99% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 380 randomly selected caterpillars observed, 58 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 99% confidence the proportion of all caterpillars that lived to become a butterfly is between   and .   b. If many groups of 380 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. ?About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about ? percent will not contain the true population proportion.

Q: 13. Suppose you have estimated that the 95 % confidence interval for B₁ is {0.750 , 0.950}. Which of…

A: Given that  Suppose you have estimated that the 95 % confidence interval for B₁ is {0.750 , 0.950}.…

Q: For each of the following statements, specify whether the statement is a correct interpretation of…

A: 95% confidence interval means, the range of values for which we can be 95% sure that the range…

Q: A If n=21, ¯x (x-bar)=34, and s=8, construct a confidence interval at a 98% confidence level. Assume…

A:

Q: The figure to the right shows the results of a survey in which 1018 adults from Country A 1015…

A: Given Information: Country Sample size (n) Sample proportion (p^) A 1018 0.37 B 1015 0.19 C…

Q: If n 19, x =40, and s = 20, construct a confidence interval at a 80% confidence level.

A:

Q: Suppose you decide that you want to construct a 93% confidence interval. Which one of the following…

A: Given : confidence level, c = 93 %

Q: You observe 60 customers at a coffee shop, and 82% of them tip. What is the 95% confidence interval…

A: Given : You observe 60 customers at a coffee shop, and 82% of them tip.

Q: If n=24, x(x-bar)%=D30, and s=7, construct a confidence interval at a 98% confidence level. Assume…

A: The random variable X follows normal distribution. The sample size is 24. The sample mean is 30. The…

Q: The sports section of the East Mule Shoe Gazette runs a weekly question that readers can answer…

A:

Q: In terms of z scores, a 95% confidence interval consists of which of the following ranges? 1. ±1 z

A: Given, Z=x-μσ where, x= observed value μ=mean of the sample σ=standard deviation

Q: If n-28, 2(x-bar)-38, and s-13, construct a confidence interval at a 98% confidence level. Assume…

A: Given : Sample Size, n = 28 Sample Mean, x̄ = 38 sample standard…

Q: The. Nielsen television ratings used a random sample of 2,000 homes and found that 45% of the homes…

A:

Q: If n=32, x(x-bar)=47, and s=18, construct a confidence interval at a 99% confidence level. Assume…

A: Given that  Sample size n =32 Sample mean =47 Standard deviation =18

Q: Which of the following statements is true regarding the width of a confidence interval for a…

A: Solution : The width of a confidence interval for a population proportion is narrower when the…

Q: You are interested in constructing a 95% confidence interval for the proportion of all caterpillars…

A:

Q: Suppose you want to construct a 95% confidence interval for the proportion of people who will stop…

A: We have given that,  Margin of error (E) = ± 4% = ±0.04 and confidence interval = 95% Then,  We will…

Q: Maria has data from a random sample of 16 subjects and is constructing a 95% confidence interval for…

A:

Q: A sample of 1000 adults showed that 31% of them are smokers. The 90% confidence interval for the…

A: Solution: From the given information, n=1000, p=0.31 and the confidence level is 0.90. Then, the…

Q: If a sample of n = 22 scores is being used to make an 90% confidence interval estimate of the…

A: Using t-table: Refer t-distribution table and look for the "t" value corresponding to degrees of…

Q: In order to make the decision for one business, your team constructed a 90% confidence interval, the…

A: For 90% confidence interval, the width of that confidence interval is 500.We have to reduce the…

Q: Wildlife biologists inspect 153 deer taken by hunters and find that 32 of them carry ticks that test…

A:

Q: 1. In a recent study, the researchers want to find the information about the percentage of adults…

A: Given datan = 3026proportion of people who prefer to get their news online = 0.38

Q: A scientist computes a 90% confidence interval to be (4.38, 6.02). Using the same data, she also…

A:

Q: A simple random sample of 120 vet clinics in the Midwest reveals that the vast majority of clinics…

A: Given that  Sample size n =120 Favorable cases x =88 Sample proportion p^=x/n  =88/120 =0.7333

Q: In describing the findings of a 2010 Public ReligionResearch Institute poll, the researchers…

A: Margin of error (E)= Z * SE   As the confidence interval increases z-value also increases. Example:…

Q: Beth wants to determine a 99 percent confidence interval for the true proportion p of high school…

A:

Q: Beth wants to determine a 95 percent confidence interval for the true proportion p of high school…

A: Here we need to find the required sample size inorder to construct a 95% confidence interval for the…

Q: Here are summary statistics for randomly selected weights of newborn​ girls: n=187​, x=30.6 ​hg,…

A: Given data: First sample: The statistics for the weights of randomly selected newborn girls is,…

Q: Dylan wants to determine a 99 percent confidence interval for the true proportion p of high school…

A:

Q: An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars…

A:

Q: A study was conducted to determine if the percent of women who received financial aid is different…

A: a. 90% confidence interval for the differences in financial aid rates between men and women is-…

Q: Dylan wants to determine a 99 percent confidence interval for the true proportion p of high school…

A:

Q: Suppose that 18% of a random sample of 2307 Miami residents said that they will donate blood in…

A: The sample proportion is given as 0.18. The sample size is given as 2307. The two-tailed z-critical…

Q: In a harvest of 50 watermelons, farmers prefer at least 72% of watermelons to be classified as…

A:

Q: In a certain high school, 7 out of 11 juniors said that they planned to go to the winter prom.…

A:

Q: The figure to the right shows the results of a survey in which 996 adults from Country A, 1006…

A:

Q: Beth wants to determine a 90 percent confidence interval for the true proportion p of high school…

A: The required margin of error (E) is less than 0.04. The sample proportion p^ is 0.50 (because…

Q: if n=20, x=43, and s=9, construct a confidence interval at a 98% confidence level, the data came…

A:

Q: Which of the following statements is true regarding the width of a confidence interval for a…

A:

Q: Suppose you didn’t know whether the coin was fair or not and you wanted to determine a 95%…

A: It is given that sample size (n) is 16,000 and x is 8040.

Q: how many samples out of 100 would you expect to not include the true population mean within their…

A: here given ,  confidence level =  90%  sample size  = 100

Q: Which alternative hypotheses will allow you to determine statistical significance at α = 0.05 using…

A: In general, two-tail critical value is computed to obtain confidence interval.

Q: Which is true about a 95% confidence interval for a population proportion based on a given sample? A…

A: The given information about the 95% confidence interval for a population proportion.

Q: A sample of 100 components is drawn, and a 95% confidence interval for the proportion defective…

A:

Q: Which of the following would result in the widest confidence interval? a) A sample size of 100 with…

A: Form the above question Which of the following would result in the widest confidence interval The…

Q: 95% confidence interval for the proportion of college students who have texted during class was…

A: Given that  95% confidence interval=(0.75 , 0.95)

Q: Ellie and Alec are each attempting to estimate the proportion of coffee drinkers who consume more…

A: Solution Given Ellie’s interval is from 0.286 to 0.514, and Alec’s interval is from 0.346 to 0.474.

Q: For one NBA playoff game the actual percentage of the television viewing public who watched the game…

A: Given information: PWatching the game=24%=24100=0.24n=50

Q: Express the confidence interval in the form of p±E. 13) 0.203<p<1.423 13)

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.