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You pull a 65kg box up a frictionless ramp at an angle of 15o with a rope that is parallel to the incline and with a tension equal to 250N. What is the box's acceleration up the ramp?

Question

You pull a 65kg box up a frictionless ramp at an angle of 15o with a rope that is parallel to the incline and with a tension equal to 250N. What is the box's acceleration up the ramp?

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Step 1

the equilibrium condition along the ramp is 

T -mg sin
ma
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T -mg sin ma

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Step 2

substitute the givne quantities in the above ...

250 N-(65 kg) (9.8m/s2) sin 15° = (65kg)a
85.1N- (65kg)a
85.1N
a
65kg
=131m/s
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250 N-(65 kg) (9.8m/s2) sin 15° = (65kg)a 85.1N- (65kg)a 85.1N a 65kg =131m/s

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