Zinc and magnesium metal each react with HCl according to the following equation:Zn + 2 HCl= ZnCl2 + H2Mg + 2 HCl = MgCl2 + H2A 10.00 g mixture of zinc and magnesium is reacted with just enough of HCl so that all the zinc and magnesium in the mixture have reacted and no excess HCl is added. The resulting solution requires 156 mL of 3.00 M silver nitrate to precipitate all the Cl- ions in the solution to form silver chloride. Calculate the percent by mass of magnesium in the original mixture. (2)

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Asked Dec 10, 2019
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  1. Zinc and magnesium metal each react with HCl according to the following equation:

Zn + 2 HCl= ZnCl2 + H2

Mg + 2 HCl = MgCl2 + H2

A 10.00 g mixture of zinc and magnesium is reacted with just enough of HCl so that all the zinc and magnesium in the mixture have reacted and no excess HCl is added. The resulting solution requires 156 mL of 3.00 M silver nitrate to precipitate all the Cl- ions in the solution to form silver chloride. Calculate the percent by mass of magnesium in the original mixture. (2)

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Step 1
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veactious ave shorm belori: given The → Zncl2 t H2 + Hz zn + 2 Hce + 2H4 → Mgclz mg Mass ef mixture l0.00

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Step 2
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The veaction shonm belom: (mixture) witu Ha is Zn and + UHCI –→ + 2H2 Znlz t Mgclz

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Step 3
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The mixture requives 156 mL o to precipitate. The reaction ok AGNO2 witu the ve is shorm belom! 3.00M bilver nitate eculting mixture + zn(wod),t nylwe); (2) gagmies Zncy t Mgcb tHagOs- ¡NO3 That weans, 4 moles y agaios, I mde I mole of Mac2 veact to produce "producls $ Znclz and

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