Question
Asked Sep 26, 2019
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Zinc reacts with hydrochloric acid according to the reaction equation

 

Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g)
 

How many milliliters of 6.00 M HCl(aq) are required to react with 6.95 g Zn(s)?

 

volume: _______ mL
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Expert Answer

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Step 1

Given:

Mass of Zn = 6.95 g.

Molar mass of Zn = 65.38 g/mol.

Molarity of HCl = 6.0 M.

Balanced chemical reaction is given by:

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Zn(S) 2HC1(aq) -» ZnCl2(aq) H2 (g)

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Step 2

Calculation for number of moles of Zn:

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Mass Number of moles = Molar mass 6.95 g Number of moles 65.38 g/mol Number of moles 0.106 moles.

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Step 3

Calculation of number of moles of HCl:

From the above balanced chemical reac...

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1 mol of Zn 2 mol of HCl 0.106 mol of Zn -»x molof HCl 0.106 mol of Zn X 2 mol of HCl х- 1 mol of Zn 0.212 mol HCl x

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