# Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 5.50 M HCl(aq) are required to react with 2.15 g Zn(s)?

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Zinc reacts with hydrochloric acid according to the reaction equation

Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g)

How many milliliters of 5.50 M HCl(aq) are required to react with 2.15 g Zn(s)?

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Number of moles of HCl needed to react with... help_outlineImage TranscriptioncloseMass No. of moles of Zn Molar mass 2.15 g =0.0329 mol 65.38 g/mol 1 mol Zn reacts with 2 mol HCl. Hence, 0.0329 mol Zn x 2 mol HCl No.of moles of HCl reacted 0.0329 mol Zn = 1 mol Zn =0.0658 mol HCl fullscreen

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