Question
Asked Oct 3, 2019
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Zinc sulfide reacts with oxygen according to the reaction

2ZnS(s)+3O2(g)→2ZnO(s)+2SO2(g)

A reaction mixture initially contains 3.8 molZnS and 9.9 molO2.

Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant remains?        
Express your answer using two significant figures.
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Expert Answer

Step 1

The balanced Zinc oxidation reaction shown in below

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Step 2

3.8 moles of ZnS would react completely with 3.8 x (3/2) = 5.7 moles of O2, but there is mor...

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Image Transcriptionclose

(99 mdl Ojniially) - (5.7 шol Oдеacded) - 42 mel 0, lef over

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ScienceChemistry

Inorganic Chemistry

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