Zn metal reacts with hydrochloric acid according to the balanced equation Zn(s) + 2 HCl(aq) ĺZnCl2(aq) +H2(g) . When 1.00 g of Zn metal is completely reacted with 100.0 g of 0.500 M HCl(aq) in a constant-pressure calorimeter, the temperature of the solution was observed to rise from 20.30ºC to 30.50ºC. What is the change in enthalpy for the reaction (as written) per mole of Zn(s)? Use 4.18 J/g·ºC for the specific heat capacity of the solution. Assume no heat is lost to the surroundings.

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Asked Dec 16, 2019
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Zn metal reacts with hydrochloric acid according to the balanced equation Zn(s) + 2 HCl(aq) ĺZnCl2(aq) +H2(g) . When 1.00 g of Zn metal is completely reacted with 100.0 g of 0.500 M HCl(aq) in a constant-pressure calorimeter, the temperature of the solution was observed to rise from 20.30ºC to 30.50ºC. What is the change in enthalpy for the reaction (as written) per mole of Zn(s)? Use 4.18 J/g·ºC for the specific heat capacity of the solution. Assume no heat is lost to the surroundings.

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Step 1

Given data:

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Mass of Zn metal =1.00 g Mass of HCl =100.0 g Initial temperature(T, ) = 20.30 °C final temperature(T, ) = 30.50 °C Specific heat of the solution (c) = 4.18 J/g-°C

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Step 2

When 1.00 g of Zn metal completely reacts with 100.0 g of HCl, it forms ZnCl2 and hydrogen gas. The corresponding reaction is shown below.

 

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Zn (s) + 2HCI(аq) -> ZnCl, (aq) +Н. (g)

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Step 3

Therefore, the mass of the solution is the sum of ...

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Mass of solution(m) =Mass of Zn +Mass of HCl =1.00 g +100.0 g =101.0 g

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