Zorch, an archenemy of Superman, decides to slow Earth’s rotation to once per 28.0 h by exerting an opposing force at and parallel to the equator. Superman is not immediately concerned, because he knows Zorch can onlyexert a force of 4.00×107 N (a little greater than a Saturn V rocket’s thrust). How long must Zorch push with this force to accomplish his goal? (This period gives Superman time to devote to other villains.) Explicitly show how you follow the steps found in Problem-Solving Strategy for Rotational Dynamics.

Zorch, an archenemy of Superman, decides to slow Earth’s rotation to once per 28.0 h by exerting an opposing force at and parallel to the equator. Superman is not immediately concerned, because he knows Zorch can onlyexert a force of 4.00×107 N (a little greater than a Saturn V rocket’s thrust). How long must Zorch push with this force to accomplish his goal? (This period gives Superman time to devote to other villains.) Explicitly show how you follow the steps found in Problem-Solving Strategy for Rotational Dynamics.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 30P: A point on a rotating turntable 20.0 cm from the center accelerates from rest to a final speed of...

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Zorch, an archenemy of Superman, decides to slow the Earth's rotation to once per 39.5 h by exerting an opposing force at the equator and parallel to it. Superman is not immediately concerned, because he knows Zorch can only exert a force of 3.20 107 N (comparable to a Saturn V rocket's thrust). Assume the Earth's initial rotation is exactly once per 24.0 h to find how long Zorch must push with this force to accomplish his goal. (This gives Superman time to devote to other villains. The Earth's mass is 5.98 1024 kg and its radius is 6.38 106 m.)
Zorch, an archenemy of Superman, decides to slow Earth’s rotation to once per 28.0 h by exerting an opposing force at and parallel to the equator. Superman is not immediately concerned, because he knows Zorch can only exert a force of 4.00X10 N (a little greater than a Saturn V rocket’s thrust). How long must Zorch push with this force to accomplish his goal? (This period gives Superman time to devote to other villains.) Explicitly show how you follow the steps found in Problem-Solving Strategy for Rotational Dynamics.
A body is being spun by a piece of string in a horizontal circle of radius 2.50 mon a flat, frictionless surface. It spins at a rate of 3.5 rev/s. If the tension in the string is 3.0 kN, what is the mass of thebody (in kg) being spun? answer: 2.5kg
A 1.80 kg toy race car is slowing down while travelling around a circular horizontal track. If the track has a diameter of 1.51 m and the coefficient of rolling friction between the track and the race car is 0.260, what is the magnitude of angular acceleration?
In the figure, block 1 has mass m1 = 450 g, block 2 has mass m2 = 520 g, and the pulley is on a frictionless horizontal axle and has radius R = 5.0 cm. When released from rest, block 2 falls 78 cm in 4.9 s without the cord slipping on the pulley. (a) What is the magnitude of the acceleration of the blocks? What are (b) tension T2 (the tension force on the block 2) and (c) tension T1 (the tension force on the block 1)? (d) What is the magnitude of the pulley’s angular acceleration? (e) What is its rotational inertia? Caution: Try to avoid rounding off answers along the way to the solution. Use g = 9.81 m/s2.
From information on the endsheets of this book, compute, for a point located on the surface of the Earth atthe equator, the radial acceleration due to the rotationof the Earth about its axis.
A planet orbits a star, in a year of length 3.51 x 107 s, in a nearly circular orbit of radius 3.92 x 1011 m. With respect to the star, determine (a) the angular speed of the planet, (b) the tangential speed of the planet, and (c) the magnitude of the planet's centripetal acceleration.
How fast (in rpm) must a centrifuge rotate if a particle 6.7 cm from the axis of rotation is to experience an acceleration of 200000 g’s? Express your answer using two significant figures
In the figure, block 1 has mass m1 = 480 g, block 2 has mass m2 = 540 g, and the pulley is on a frictionless horizontal axle and has radius R = 5.4 cm. When released from rest, block 2 falls 77 cm in 5.1 s without the cord slipping on the pulley. (a) What is the magnitude of the acceleration of the blocks? What are (b) tension T2 (the tension force on the block 2) and (c) tension T1 (the tension force on the block 1)? (d) What is the magnitude of the pulley’s angular acceleration? (e) What is its rotational inertia? Caution: Try to avoid rounding off answers along the way to the solution. Use g = 9.81 m/s2. (A) Number: Unit: (B) Number: Unit: (C) Number: Unit: (D) Number: Unit: (E) Number: Unit:
Even though an object can have a constant tangential speed, the acceleration of an object in circular motion can NEVER be ____________________. A. zero B. less than the value of the speed C. equal to the value of the centripetal force.
In the figure, block 1 has mass m1 = 460 g, block 2 has mass m2 = 520 g, and the pulley is on a frictionless horizontal axle and has radius R = 5.0cm. When released from rest, block 2 falls 74 cm in 5.4 s without the cord slipping on the pulley. (a)What is the magnitude of the acceleration of the blocks? What are (b) tension T2 (the tension force on the block 2) and (c) tension T1 (the tension force on the block 1)? (d) What is the magnitude of the pulley’s angular acceleration? (e) What is its rotational inertia? Caution: Try to avoid rounding off answers along the way to the solution. Use g = 9.81 m/s2.
Assume the earth is a uniform sphere of mass M and radius R. As strange as it may sound, if one can dig a long tunnel from one side of the Earth straight through the center and exit the other end, any object falling into the tunnel will appear at the other end (i.e. the opposite side of the Earth) in just 2530 s (42.2 min). Call that time t. Let t be a function of G, M, and R, where G = 6.67 x 10^-11 m3 kg−1 s−2 is the Universal Gravitational Constant, M = 5.98 x 10^24 kg, and R = 6400 km. (a) From dimensional analysis alone find the expression for t, up to a numerical constant c.(b) Determine the value of c by using the above values in the expression found in part (a).