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Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248

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Chapter
Section
BuyFindarrow_forward

Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248
Textbook Problem

Calculate each expression in Exercises 1–24, giving the answer as a whole number or a fraction in lowest terms.

3 ( 1 ( 1 2 ) 2 ) 2 + 1

To determine

To calculate: The value of the expression 3(1(12)2)2+1 in the form of whole number or a fraction in the lowest form.

Explanation

Given Information:

The provided expression is 3(1(12)2)2+1.

Formula used:

Standard Order of Operations:

Step 1: Simplify the expressions within the parentheses.

Step 2: Simplify the numerator and denominator separately.

Step 3: Simplify the exponent and apply the necessary operations.

Calculation:

Consider the provided expression 3(1(12)2)2+1.

Now solve the values within the parentheses,

3(1(12)2)2+1=3(114)2+1=3(414)2+1

Now simplify further,

3(1(1

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