   Chapter 0.2, Problem 27E

Chapter
Section
Textbook Problem

Simplify each expression in Exercises 17–30, expressing your answer in positive exponent form. ( x y − 2 z x − 1 z ) 3

To determine

To calculate: The simplified form of the expression (xy2zx1z)3

Explanation

Given Information:

The provided expression is (xy2zx1z)3.

Formula used:

For any real number a,

(an)m=anm

For any real number a other than 0,

aman=amn

Where a is the base and m, n are exponents of numerator and denominator respectively.

For any real numbers a, b

(ab)n=anbn

Where a, b are base entities and n is the exponent.

For any real value a.

an=1an=1a×a×aa(n times)

Where a is the base and n is the negative integer exponent.

Calculation:

Consider the provided expression (xy2zx1z)3, this can also be written as {(xx1)(y21)(zz)}3.

Now use the exponent identity aman=amn, and simplify

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