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Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248

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Section
BuyFindarrow_forward

Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248
Textbook Problem

Simplify each expression in Exercises 17–30, expressing your answer in positive exponent form.

( x 2 y 1 z 0 x y z ) 2

To determine

To calculate: The simplified form of the expression (x2y1z0xyz)2.

Explanation

Given Information:

The provided expression is (x2y1z0xyz)2.

Formula used:

For any real number a,

(an)m=anm

For any real number a other than 0,

aman=amn

Where a is the base and m, n are exponents of numerator and denominator respectively.

For any real numbers a, b

(ab)n=anbn

Where a, b are base entities and n is the exponent.

For any real value a.

an=1an=1a×a×aa(n times)

Where a is the base and n is the negative integer exponent.

Calculation:

Consider the given expression (x2y1z0xyz)2, this can also be written as {(x2x)(y1y)(z0z)}2.

Use the exponent identity aman=amn, and simplify

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