   Chapter 0.2, Problem 29E

Chapter
Section
Textbook Problem

Simplify each expression in Exercises 17–30, expressing your answer in positive exponent form. ( x − 1 y − 2 z 2 x y ) − 2

To determine

To calculate: The simplified form of the expression (x1y2z2xy)2.

Explanation

Given Information:

The given expression is (x1y2z2xy)2.

Formula used:

For any real number a,

(an)m=anm

For any real number a other than 0,

aman=amn

Where a is the base and m, n are exponents of numerator and denominator respectively.

For any real numbers a, b

(ab)n=anbn

Where a, b are base entities and n is the exponent.

For any real value a.

an=1an=1a×a×aa(n times)

Where a is the base and n is the negative integer exponent.

Calculation:

Consider the given expression (x1y2z2xy)2.

This can be re arranged as (x1y2z2xy)2={(x1x)(y2y)(z21)}2

Now use the exponent identity aman=amn and simplify the expression

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