   Chapter 0.2, Problem 36E

Chapter
Section
Textbook Problem

Convert the expressions in Exercises 31-36 to positive exponent form. 1 3 x − 4 + 0.1 x − 2 3

To determine

To calculate: The positive exponent form of the expression 13x4+0.1x23.

Explanation

Given Information:

The given expression is 13x4+0.1x23.

Formula used:

For any real value a.

an=1an=1a×a×aa(n times)

Where a is the base and n is the negative integer exponent.

Calculation:

Consider the given expression 13x4+0.1x23.

This expression can be written as 13x4+0.1x23=(13×1x4)+(0

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Sketch the graphs of the equations in Exercises 512. x+y=1

Finite Mathematics and Applied Calculus (MindTap Course List)

Calculate y'. 48. y=xtanh1x

Calculus: Early Transcendentals

Write the number in polar form with argument between 0 and 2. 25. 3 + 3i

Single Variable Calculus: Early Transcendentals, Volume I

Explain in your own words the meaning of limxf(x)=L and limxf(x)=M.

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

Show that (nk)=(nnk). Give an interpretation involving subsets.

Probability and Statistics for Engineering and the Sciences

State both parts of the Fundamental Theorem of Calculus.

Single Variable Calculus: Early Transcendentals

Suppose . Then F(x)g(x) + C f′(g(x)) + C F(g′(x)) + C F(g(x)) + C

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th

Let A=. a. Find A1. b. Show that (A1)1=A.

Finite Mathematics for the Managerial, Life, and Social Sciences 