   Chapter 0.3, Problem 19E

Chapter
Section
Textbook Problem

Expand each expression in Exercises 1–22. ( x 2 − 2 x + 1 ) 2

To determine

To calculate: The expanded form of the expression (x22x+1)2.

Explanation

Given Information:

The provided expression is, (x22x+1)2

Formula used:

The distributive law,

(a±b)c=ac±bc

Where, a, b and c are any real numbers.

Calculation:

Consider the provided expression,

(x22x+1)2

Rewrite the expression as below,

(x22x+1)(x22x+1)

Apply the distributive law as below,

(x22x+1)(x22x+1)=(x2)(x22x+1)+(2x)(x22x+1)+(1)(x22x+1)=((x2)(x2)+(x2)(2x)+(x2)(1)+(2x)(

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