   Chapter 0.3, Problem 21E

Chapter
Section
Textbook Problem

Expand each expression in Exercises 1–22. ( y 3 + 2 y 2 + y ) ( y 2 + 2 y − 1 )

To determine

To calculate: The expanded form of the expression (y3+2y2+y)(y2+2y1).

Explanation

Given information:

The expression, (y3+2y2+y)(y2+2y1).

Formula used:

The distributive law,

(a±b)c=ac±bc

Where, a, b and c are any real numbers.

Calculation:

Consider the expression,

(y3+2y2+y)(y2+2y1)

Apply the distributive law as below,

(y3+2y2+y)(y2+2y1)=(y3+2y2+y)(y2)+(y3+2y2+y)(2y)+(y3+2y2+y)(1)=((y3)(y2)+(2y2)(y2)+(y)(y2)+(y3)(2y)+(2y2)(2y)+(y)(2

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