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Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248

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Section
BuyFindarrow_forward

Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248
Textbook Problem

Expand each expression in Exercises 1–22.

( x 3 2 x 2 + 4 ) ( 3 x 2 x + 2 )

To determine

To calculate: The expanded form of the expression (x32x2+4)(3x2x+2).

Explanation

Given information:

The expression, (x32x2+4)(3x2x+2).

Formula used:

The distributive law,

(a±b)c=ac±bc

Where, a, b and c are any real numbers.

Calculation:

Consider the expression,

(x32x2+4)(3x2x+2)

Apply the distributive law as below,

(x32x2+4)(3x2x+2)=(x32x2+4)(3x2)+(x32x2+4)(x)+(x32x2+4)(2)=((x3)(3x2)+(2x2)(3x2)+(4)(3x2)+(x3)(x)+(2x2

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