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Math
CalculusApplied Calculus7th Edition

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Chapter 0.3, Problem 42E
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Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248

Solutions

Chapter
Section
Problem 1E
Problem 2E
Problem 3E
Problem 4E
Problem 5E
Problem 6E
Problem 7E
Problem 8E
Problem 9E
Problem 10E
Problem 11E
Problem 12E
Problem 13E
Problem 14E
Problem 15E
Problem 16E
Problem 17E
Problem 18E
Problem 19E
Problem 20E
Problem 21E
Problem 22E
Problem 23E
Problem 24E
Problem 25E
Problem 26E
Problem 27E
Problem 28E
Problem 29E
Problem 30E
Problem 31E
Problem 32E
Problem 33E
Problem 34E
Problem 35E
Problem 36E
Problem 37E
Problem 38E
Problem 39E
Problem 40E
Problem 41E
Problem 42E
Problem 43E
Problem 44E
Problem 45E
Problem 46E
Problem 47E
Problem 48E
BuyFindarrow_forward

Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248
Textbook Problem

In Exercises 31–48, (a) factor the given expression, and (b) set the expression equal to zero and solve for the unknown (x in the odd-numbered exercises and y in the even-numbered exercises.)

6 y 2 + 17 y + 12

(a)

To determine

To calculate: The factors of the expression 6y2+17y+12.

Explanation

Given information:

The expression, 6y2+17y+12.

Formula used:

Steps to calculate the factors of quadratic equation ax2+bx+c by trial and error method,

Step1: Factor ax2 as (a1x)(a2x) with a1 positive.

Step2: Factor c as c1c2.

Step 3: Check if ax2+bx+c=(a1x±c1)(a2x±c2)

If yes, then (a1x±c1)(a2x±c2) are the factors.

Step 4: If not, try other factorization of ax2 and c and repeat all the steps.

The distributive law,

(a±b)c=ac±bc

Where, a, b and c are any real numbers.

Calculation:

Consider the expression,

6y2+17y+12

Factor of 6y2 are (6y)(y) and(2y)(3y).

The factors of 12 are (1)(12),(2)(6),(3)(4),(4)(3),(6)(1) and(12)(1) 

(b)

To determine

To calculate: The value of y when the expression 6y2+17y+12 is equal to zero.

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