   Chapter 0.6, Problem 19E

Chapter
Section
Textbook Problem

Solve the equations in Exercises 1–26. x − 1 x = 0

To determine

To calculate: The solution of the equation x1x=0.

Explanation

Given information:

The equation is x1x=0.

Formula used:

Formula for difference of two squares,

(a+b)(ab)=a2b2

Where, a and b are real numbers.

Zero product property,

If ab=0 then either a=0 or b=0.

Condition to solve an equation of the form PQ=0,

If PQ=0, then P=0.

Calculation:

Consider the expression,

x1x=0

Make the denominator of both the term equal as below,

xx1x1x=0x2x1x=0x21x=0

As the above equation is in PQ=0 form

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